A particle performs a simple harmonic motion (SHM). The displacement x as a function of time t is given as x = 4 cos(1.25 t). 1. What is the time period of this motion? A.5.03 s • B.1.25 s • C.8.0 s D.4.0 s 2. What is the magnitude of the maximum acceleration for this SHM? • A.4.00 m/s² • B.6.25 m/s² C.1.25 m/s² • D.5.00 m/s²

icon
Related questions
Question
100%

3) find the values in this question.

A particle performs a simple harmonic motion (SHM). The displacement x as a function of time t is
given as x = 4 cos(1.25 t).
1. What is the time period of this motion?
• A.5.03 s
• B.1.25 s
• C.8.0 s
• D.4.0 s
2. What is the magnitude of the maximum acceleration for this SHM?
• A.4.00 m/s²
• B.6.25 m/s
• C.1.25 m/s²
• D.5.00 m/s²
Transcribed Image Text:A particle performs a simple harmonic motion (SHM). The displacement x as a function of time t is given as x = 4 cos(1.25 t). 1. What is the time period of this motion? • A.5.03 s • B.1.25 s • C.8.0 s • D.4.0 s 2. What is the magnitude of the maximum acceleration for this SHM? • A.4.00 m/s² • B.6.25 m/s • C.1.25 m/s² • D.5.00 m/s²
Expert Solution
steps

Step by step

Solved in 5 steps

Blurred answer