A particle P projected from a point O on horizontal ground hits the ground after 2.4 seconds. The horizontal component of the initial velocity of P is 5/3 d ms-1 The speed of P as it passes over the wall is 16ms-1 (d) Find the value of d correct to 3 significant figures.
A particle P projected from a point O on horizontal ground hits the ground after 2.4 seconds. The horizontal component of the initial velocity of P is 5/3 d ms-1 The speed of P as it passes over the wall is 16ms-1 (d) Find the value of d correct to 3 significant figures.
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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A particle P projected from a point O on horizontal ground hits the ground after 2.4 seconds.
The horizontal component of the initial velocity of P is 5/3 d ms-1
The speed of P as it passes over the wall is 16ms-1
(d) Find the value of d correct to 3 significant figures.
May I have the answer for D please as the rules is only to do 3 of them so I asked separately
![b Answered: A particle P projecte X
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A particle P projected from a point O on horizon...
Tw=s
S
On dividing the values,
Tw=0.6 s
y=11.76 ms-1
Step 5
On considering let height
wall is h
h = yTw + (5)g(Tw)²
Where,
g is the acceleration due to gravity
On substituting the corresponding values to the above expression,
h = (11. 76) (0. 6) + (0. 5) (–9. 8) (0. 6) (0. 6)
h = 7.056 – 1.764
h = 5. 292 m
Step 6
As per rules supposed to solve only first three subparts of the question so please post the remaining questions
as a separate one
IMG_1274.heic
全部顯示](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff50bd6ab-e1f5-4029-9831-bf2ced3d1f6b%2F3a9be90c-bbe8-46f2-af8c-e8f340f7fec4%2F3a0nbw_processed.png&w=3840&q=75)
Transcribed Image Text:b Answered: A particle P projecte X
+
bartleby.com/questions-and-answers/a-particle-p-projected-from-a-point-o-on-horizontal-ground-hits-the-ground-after-2.4-seconds.-t...
7094
= bartleby
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A particle P projected from a point O on horizon...
Tw=s
S
On dividing the values,
Tw=0.6 s
y=11.76 ms-1
Step 5
On considering let height
wall is h
h = yTw + (5)g(Tw)²
Where,
g is the acceleration due to gravity
On substituting the corresponding values to the above expression,
h = (11. 76) (0. 6) + (0. 5) (–9. 8) (0. 6) (0. 6)
h = 7.056 – 1.764
h = 5. 292 m
Step 6
As per rules supposed to solve only first three subparts of the question so please post the remaining questions
as a separate one
IMG_1274.heic
全部顯示
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