A particle of rest mass mo has a kinetic energy k. Its de-Broglie wavelength is- hc hc (A) A = (B) 1 = Vk+ 2moc? Vk (k + 2moc²) (D) 1 = Vk (C) A = V2moc2

icon
Related questions
Question
100%
Please do 113
ure- 113. A particle of rest mass mo has a kinetic energy k.
= At,
tain
Its de-Broglie wavelength is-
hc
hc
(A) 2 =
(B ) λ
Vk + 2moc?
Vk (k + 2moc2)
(C) =
(D) =
V 2moc2
114. The angular momentum of an atomic electron is-
(A) Not quantized
nent
(B) Quantized in magnitude and direction both
(C) Quantized in magnitude only
(D) Quantized in direction only
the
115. A hydrogen atom remains in its ground state when
electron-
(A) Resides inside the nucleus
(B) Escape from the atom
(C) Is in its first orbital
(D) Does not orbit round but is stationary
116. For a spherically symmetric probability cloud of
an electron-
(A) Principal quantum number is zero
(B) Orbital quantum number is zero
(C) Magnetic quantum number is zero
(D) Spin quantum number is zero
ave
cles
Transcribed Image Text:ure- 113. A particle of rest mass mo has a kinetic energy k. = At, tain Its de-Broglie wavelength is- hc hc (A) 2 = (B ) λ Vk + 2moc? Vk (k + 2moc2) (C) = (D) = V 2moc2 114. The angular momentum of an atomic electron is- (A) Not quantized nent (B) Quantized in magnitude and direction both (C) Quantized in magnitude only (D) Quantized in direction only the 115. A hydrogen atom remains in its ground state when electron- (A) Resides inside the nucleus (B) Escape from the atom (C) Is in its first orbital (D) Does not orbit round but is stationary 116. For a spherically symmetric probability cloud of an electron- (A) Principal quantum number is zero (B) Orbital quantum number is zero (C) Magnetic quantum number is zero (D) Spin quantum number is zero ave cles
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer