A particle of mass m is suspended from the ceiling of a hollow block by a massless cord as shown in the figure. The block is pulled up a wedge that makes an angle D with the horizontal at a constant accelaration a. If the cord makes a constant angle 0 the perpendicular to the ceiling, what is a in terms of , 0 and gravitational acceleration g. --

Q: load devil like the one shown in Figure is used to move a 120 kg load with an acceleration of 1.2…

A: According to Newton's second law F = ma

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A: Given data The upward normal force is N1=620 N  The weight of the passenger is W1=650 N Let the…

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A: Net force vector Fnet=19.0 Ncos12.5i^+19.0 Nsin12.5j^+-11.5 Ni^+-17.5 Nj^=7.05 Ni^-13.4 Nj^…

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A:

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A: Solution: Mass of the woman M=55 kg, mass of the package m=8 kg and, acceleration of the lift going…

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A: Given: The electricity produced is 40 W. The requirement is 24 kWh/day.

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A: Given data: Mass of fireman is, m=80.0 kg. Magnitude of acceleration is, a=3.00 m/s2.

Q: A force  F1= 16N  is applied to an object with the mass m = 2 kg to move it across the surface…

A: Applied force = F1 = 16 N Friction force = f = F2 = 8 N Mass = m = 2 kg

Q: Two blocks, with masses m=3.6 kg and M=7.1 kg, are connected by a lightweight wire that's shown in…

A: Given data:    m=3.6 kg  M=7.1 kg  θ=55O   Coefficient of friction, μ=0.200 Applying Newton’s second…

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A:

Q: An astronaut on the moon places a package on a scale and finds its weight to be 13 N. (a) What…

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Q: On the planet Gorp there are three units of weight measure, the Zim, Dat and Sa 1 Zim=3 Dats, 14…

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Q: You want to push your 53.0 kg friend up the 33.0° ramp of a slide in a nearby park. You do so by…

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Q: A person of weight 480 N stands on a scale in an elevator. What will the scale be reading when the…

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Q: A body of mass 100 kg is weighed at the North Pole and at the equator with a spring scale. What is…

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Q: A horizontal force of 100 N pulls an 8-kg cabinet across a level floor. Find the acceleration of the…

A: Given data:  Applied force (F) = 100 N Mass (m) = 8 kg Coefficient of kinetic friction (μk) = 0.2…

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Q: a. During a rocket launch, an astronaut experiences a “g-force” (actually an acceleration) of 3.0 gs…

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Q: Two block are arranged with a massless rope and massless, frictionless pulley, as shown above. Block…

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Q: 67. In the drawing, the weight of the block on the table is 422 N and that of the hanging block is…

A: (a)  For the block on the table, T=m1aT=W1ga For the hanging block, m2g-T=m2aW2-T=W2ga

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A:

Q: The tension on the heavier mass is less than its weight. O True O False

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Q: Astrology, that unlikely and vague pseudoscience, makes much of the position of the planets at the…

A: Mass of baby,

Q: ) Listen A horizontal force of 73.0 N accelerates a 5.40 kg mass, from rest, at a rate of 1.00 m/s2…

A:

Q: A 59kg man is standing in an elevator. Determine the acceleration of the elevator if the man…

A: Given Data ; The mass of the man is given as m = 59 Kg. The apparent weight of the man is given as…

Q: The upward normal force exerted by the floor is 620 N on an elevator passenger who weighs 650 N.…

A:

Q: You are going up in an elevator. Initially the elevator accelerates for 2.0 s to 6.0 m/s. Then it…

A: The mass from the weight can be calculated using the standard formula for weight as below,

Q: Find the magnitude of the hanging block's acceleration.

A: The equations of motion are,

Q: (a) (b) (c) What is the normal force between the ramp and the box? What is the force of friction…

A: given m=20 kg (mass) θ=40o(angle of incline with horizontal) F=225 N(applied force)…

Q: 14E. A space traveler whose mass is 75 kg leaves the Earth. Compute his weight (a) on Earth, (b) on…

A:

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Q: On Neptune, a 2.50-kg object, initially at rest, falls a distance of 6 96 m in 1.12 s. The magnitude…

A: Given data: Mass (m) = 2.50 kg Initial velocity (v0) = 0 m/s Distance falls (h) = 6.96 m Time (t) =…

Newton's First Law of Motion

If a very smooth ball is rolled down an inclined surface with zero friction, the ball will continue to roll indefinitely for an infinite time, in an attempt to reach to the same height on the opposite hill!