A particle of mass (m) is executing SHM about its mean position. The total energy of the particle is given instant is-
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- a uniform rod is 1 m long and has a mass of 10 kg. it is pinned at point a, a frictionless pivot. the rod is released from a rest position 45degrees from the horizontal. the top of an undeflected ideal spring is located at point b to contact the tip of the rod when the rod is horizontal the spring has a constant of 98 kN/m. (c) assume the rod is dropped from the unknown angle, and is 10 rad/s when the rod hit the spring. What will be the maximum deflection of the spring. SHOW COMPLETE SOLUTION.Why is it only possible to produce the odd harmonics in a system with oneopen end and one closed end.A mass on a spring is held at a distance of 0.05 m from the equalibrium position. It is then released at time t=0 and undergoes simple harmonic motion. If the mass was 0.2 kg and the spring constant k was 6 Nm-1, what is the velocity of the mass at time = 7 seconds?
- thin re is measured The second harmonic frequency for a long at 200 Hz when it is attached to the ceiling with amass in tied to its bottom. Adding an extra lkg to the hanging mass increases the second harmonic Frequency to 245 M₂. Findm [draw appropriate diagrams to explain]A 5.00 g particle oscillating in simple harmonic motion has its position given bythe equation: x(t) = (2.5 cm) cos (36.5 t) At what time is the particle at the 2.00 cm mark?h wwww M A pendulum of length L = 0.61m and mass 4.8Kg has a spring of force constant k =610 N/m connected to it at a distance h = 0.35m below its point of suspension. Find the frequency 'f' of vibration of the system for small values of the amplitude (small 6). Assume the vertical suspension of length L is rigid, but ignore its mass. Use g=9.8 for gravity. Round your answer to 3 decimal places.