A particle of mass 2.0 kg moves under the influence of the force F (x) = (-5x² + 7x) N. Suppose a frictional force also acts on the particle. If the particle's speed when it starts at x = -4.0 m is 0.0 m/s and when it arrives at x = 4.0 m is 9.0 m/s, how much work is done on it by the frictional force between x = -4.0 m %3| and x = 4.0 m?
A particle of mass 2.0 kg moves under the influence of the force F (x) = (-5x² + 7x) N. Suppose a frictional force also acts on the particle. If the particle's speed when it starts at x = -4.0 m is 0.0 m/s and when it arrives at x = 4.0 m is 9.0 m/s, how much work is done on it by the frictional force between x = -4.0 m %3| and x = 4.0 m?
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Transcribed Image Text:A particle of mass 2.0 kg moves under the
influence of the force F (x) = (-5x² + 7x) N.
Suppose a frictional force also acts on the
particle. If the particle's speed when it starts at
x = -4.0 m is 0.0 m/s and when it arrives at
x = 4.0 m is 9.0 m/s, how much work is done on
it by the frictional force between x = -4.0 m
%3D
and x =
= 4.0 m?
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