A particle moving along the a-axis has its position described by the function x = (4.00t – 5.00t + 5.00) m, where t is in s. Part B At t = 2.00 s, what is the particle's veloity? Express your answer with the appropriate units. HA Vz = Value Units
A particle moving along the a-axis has its position described by the function x = (4.00t – 5.00t + 5.00) m, where t is in s. Part B At t = 2.00 s, what is the particle's veloity? Express your answer with the appropriate units. HA Vz = Value Units
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Particle Motion Along the x-axis**
A particle moving along the x-axis has its position described by the function:
\[ x = (4.00t^3 - 5.00t + 5.00) \, \text{m}, \]
where \( t \) is in seconds.
---
**Velocity Calculation**
To find the velocity \( v_x \), differentiate the position function \( x(t) \) with respect to time \( t \).
\[ v_x = \frac{d}{dt}(4.00t^3 - 5.00t + 5.00) \]
Provide your answer, including units, in the space provided next to \( v_x \).
\[ v_x = \text{Value} \quad \text{Units} \]
[Submit Button] [Request Answer Button]
---
**Part C: Acceleration Calculation**
*At \( t = 2.00 \, \text{s} \), what is the particle's acceleration?*
**Instructions:**
Differentiate the velocity function to find acceleration \( a_x \). Evaluate the acceleration at \( t = 2.00 \, \text{s} \).
Express your answer with the appropriate units.
\[ a_x = \text{Value} \quad \text{Units} \]
[Submit Button] [Request Answer Button]](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe93cb2ca-1df2-4e1a-b3ee-5d48a1415c33%2F675b8a36-9871-419e-9203-b3894f195e14%2Fu4vw8ya_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Particle Motion Along the x-axis**
A particle moving along the x-axis has its position described by the function:
\[ x = (4.00t^3 - 5.00t + 5.00) \, \text{m}, \]
where \( t \) is in seconds.
---
**Velocity Calculation**
To find the velocity \( v_x \), differentiate the position function \( x(t) \) with respect to time \( t \).
\[ v_x = \frac{d}{dt}(4.00t^3 - 5.00t + 5.00) \]
Provide your answer, including units, in the space provided next to \( v_x \).
\[ v_x = \text{Value} \quad \text{Units} \]
[Submit Button] [Request Answer Button]
---
**Part C: Acceleration Calculation**
*At \( t = 2.00 \, \text{s} \), what is the particle's acceleration?*
**Instructions:**
Differentiate the velocity function to find acceleration \( a_x \). Evaluate the acceleration at \( t = 2.00 \, \text{s} \).
Express your answer with the appropriate units.
\[ a_x = \text{Value} \quad \text{Units} \]
[Submit Button] [Request Answer Button]
![The problem involves a particle moving along the x-axis, where its position is described by the function:
\[ x = (4.00t^3 - 5.00t + 5.00) \, \text{m} \]
where \( t \) is in seconds.
**Question:**
Part B - At \( t = 2.00 \, \text{s} \), what is the particle's velocity?
Express your answer with the appropriate units.
**Answer Section:**
\[ v_x = \text{Value} \quad \text{Units} \]
Options for input and submit buttons are available, including tools for formatting equations.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe93cb2ca-1df2-4e1a-b3ee-5d48a1415c33%2F675b8a36-9871-419e-9203-b3894f195e14%2F892gnjt_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The problem involves a particle moving along the x-axis, where its position is described by the function:
\[ x = (4.00t^3 - 5.00t + 5.00) \, \text{m} \]
where \( t \) is in seconds.
**Question:**
Part B - At \( t = 2.00 \, \text{s} \), what is the particle's velocity?
Express your answer with the appropriate units.
**Answer Section:**
\[ v_x = \text{Value} \quad \text{Units} \]
Options for input and submit buttons are available, including tools for formatting equations.
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