A particle moving along a straight line starts from position x = -10 ft with an initial velocity VA = 6 ft/sec and a variable acceleration. (a) Determine the velocity of the particle at position B if the acceleration changes with position x as shown in Figure (a). (VB 9.8 ft/sec) = (b) Determine the position and velocity of the particle at time t with time as shown in Figure (b). (vg = 36 ft/sec, xB a, ft/sec² 5 a, ft/sec² 5 = 20 sec if the acceleration changes = 276.7 ft) AD -10 B x, ft 10 -4 А (a) B t, sec 10 20 -4 А (b)

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This is a Dynamics question using differential equations. Step A is 36 m/s. I need help with step b

A particle moving along a straight line starts from position x = -10 ft with an initial velocity
VA = 6 ft/sec and a variable acceleration.
(a) Determine the velocity of the particle at position B if the acceleration changes with position x
as shown in Figure (a). (VB 9.8 ft/sec)
=
(b) Determine the position and velocity of the particle at time t
with time as shown in Figure (b). (vg = 36 ft/sec, xB
a, ft/sec²
5
a, ft/sec²
5
=
20 sec if the acceleration changes
=
276.7 ft)
AD
-10
B
x, ft
10
-4
А
(a)
B
t, sec
10
20
-4
А
(b)
Transcribed Image Text:A particle moving along a straight line starts from position x = -10 ft with an initial velocity VA = 6 ft/sec and a variable acceleration. (a) Determine the velocity of the particle at position B if the acceleration changes with position x as shown in Figure (a). (VB 9.8 ft/sec) = (b) Determine the position and velocity of the particle at time t with time as shown in Figure (b). (vg = 36 ft/sec, xB a, ft/sec² 5 a, ft/sec² 5 = 20 sec if the acceleration changes = 276.7 ft) AD -10 B x, ft 10 -4 А (a) B t, sec 10 20 -4 А (b)
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