A particle moving along a straight line is subjected to a deceleration a=-2v3ms2, where V is in has a velocity v=8 m/s and a position s=10 m when t=0 sec., determine its: ms. If it 1. Velocity when t=4 sec. Position when t=4 sec. 2.

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A: dt=dva∫0tdt=∫60vdv(-0.4 v3)t=10.412v260vnow when t=4 1v260v=4×0.4×21v2-1602=3.2v=0.559 m/s