A particle moves in one dimension x under the influence of a potential V(x) as sketched in the figure below. The shaded region corresponds to infinite V, i.e., the particle is not allowed to penetrate there. V(x) a b a²Vo = If there is an energy eigenvalue E = 0, then a and Vo are related by a²Vo = (n + ²)² n² 2m 3-1 n²π² 2m a²V₁ = (n + ²) π ² 2m -Vo nπ² 0 a X
A particle moves in one dimension x under the influence of a potential V(x) as sketched in the figure below. The shaded region corresponds to infinite V, i.e., the particle is not allowed to penetrate there. V(x) a b a²Vo = If there is an energy eigenvalue E = 0, then a and Vo are related by a²Vo = (n + ²)² n² 2m 3-1 n²π² 2m a²V₁ = (n + ²) π ² 2m -Vo nπ² 0 a X
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![A particle moves in one dimension x under the influence of a potential V(x) as
sketched in the figure below. The shaded region corresponds to infinite V, i.e., the
particle is not allowed to penetrate there.
V(x)
a
b
a²Vo =
If there is an energy eigenvalue E = 0, then a and V, are related by
a²Vo =
(n + ² ) ² n²
2m
3-1
n²π²
2m
a²V₁ =
(n + ²) π ²
2m
-Vo
nπ²
0
a
X](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fce1fd4b4-7341-438f-9b56-ec007e61de74%2Fd5d7548e-7152-4e4c-b094-0be94f800dbb%2Fd8u2gjr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A particle moves in one dimension x under the influence of a potential V(x) as
sketched in the figure below. The shaded region corresponds to infinite V, i.e., the
particle is not allowed to penetrate there.
V(x)
a
b
a²Vo =
If there is an energy eigenvalue E = 0, then a and V, are related by
a²Vo =
(n + ² ) ² n²
2m
3-1
n²π²
2m
a²V₁ =
(n + ²) π ²
2m
-Vo
nπ²
0
a
X
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