A particle moves in a straight line with constant acceleration 'a'. The displacements of particle from origin in times t1, t2 and t3 are s1, s2 and s3 respectively. If times are in A.P. with common difference d and displacements are in G.P. Then prove that (/51 - V53) a =

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A particle moves in a straight line with constant acceleration 'a'. The displacements of particle from origin in times t1, t2
and t3 are s1, s2 and s3 respectively. If times are in A.P. with common difference d and displacements are in G.P. Then
prove that
a =
d?
Transcribed Image Text:A particle moves in a straight line with constant acceleration 'a'. The displacements of particle from origin in times t1, t2 and t3 are s1, s2 and s3 respectively. If times are in A.P. with common difference d and displacements are in G.P. Then prove that a = d?
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