A particle moves in a straight line with a velocity of v' (t) = /3t –1 meters per second, where t is time in seconds. At t = 2, the particle's distance from the starting point was 8 meters in the positive direction. A) Calculate the approximate position of the particle at t=8 seconds using Simpson's 3/8 rule. B) What is the True Error if by using direct integration the answer is 30.028 meters? C) What is the Absolute Relative Error?
A particle moves in a straight line with a velocity of v' (t) = /3t –1 meters per second, where t is time in seconds. At t = 2, the particle's distance from the starting point was 8 meters in the positive direction. A) Calculate the approximate position of the particle at t=8 seconds using Simpson's 3/8 rule. B) What is the True Error if by using direct integration the answer is 30.028 meters? C) What is the Absolute Relative Error?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:A particle moves in a straight line with a velocity of v' (t) = /3t – 1 meters per second,
where t is time in seconds. At t = 2, the particle's distance from the starting point was 8 meters
-
in the positive direction.
A) Calculate the approximate position of the particle at t=8 seconds using Simpson's 3/8 rule.
B) What is the True Error if by using direct integration the answer is 30.028 meters?
C) What is the Absolute Relative Error?
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