A particle moves in a straight line with a velocity of v' (t) = /3t –1 meters per second, where t is time in seconds. At t = 2, the particle's distance from the starting point was 8 meters in the positive direction. A) Calculate the approximate position of the particle at t=8 seconds using Simpson's 3/8 rule. B) What is the True Error if by using direct integration the answer is 30.028 meters? C) What is the Absolute Relative Error?

Q: Water is discharged from a pipeline at a velocity v given by the function v = 1392 p 1/2 , where p…

A:

Q: Suppose an object is moving along a line such that the acceleration after t seconds is 6t -8t…

A:

Q: A right-circular cylinder has a height which is three times its diameter. The diameter of the…

A: Given, A right circular cylinder, Diameter,2r=8cm Radius,r=82=4cm Height=3(diameter) Height=32r=6r…

Q: You are on a trip, and at time point t=3.1t=3.1 your tripmeter (the meter that tells you how many…

A:

Q: A square is measured and each side is found to be 8 inches with a possible error of at most 0.01…

A: We are given that each side of a square is 8±0.1. Let x be the side of square and then the side of…

Q: finishes draining just as the bucket reaches the 10-m level. How much work is done? (Use 9.8 m/s2…

A: A leaky 10 kg bucket is lifted from the ground to a height of 10 m at a constant speed with a rope…

Q: A particle moves on the line y = 2x + 1 in such a way that its x−coordinate changes at a constant…

A: Given line:y=2x+1.It is given that dxdt=4