A particle moves in a straight line with a constant acceleration of 24 ft/s² for 6 s,zero acceleration for the next 4 s, and a constant acceleration of 14 ft/s2 for the next 4 s.Knowing that the particle starts from the origin and that its velocity is 28 ft/s during thezero acceleration time interval, determine the position and the velocity of the particle andthe total distance traveled when t =14 s.a (ft/s?)4.61014t(s)-43.A particle moves in a straight line with the velocity shown in the figure. Knowingthat x=-48 ft at t= 0, determine (a) the maximum value of the position coordinate of theparticle, (b) the values of t for which the particle is at a distance of 108 ft from the origin.v(ft/s)1824 301018t (s)-18

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