A particle moves in a circular path of radius 0.15 m with a constant angular speed of 5.0 rev/s. The acceleration of the particle is 986 m/s² 1600 m/s² 0.31 m/s² O 7.5 m/s² O 148 m/s²

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

A particle moves in a circular path of radius 0.15 m with a constant angular speed of 5.0 revolutions per second. The acceleration of the particle is:

- ○ 986 m/s²
- ○ 1600 m/s²
- ○ 0.31 m/s²
- ○ 7.5 m/s²
- ○ 148 m/s²

**Explanation:**

To find the acceleration of the particle moving in a circular path, we use the formula for centripetal acceleration:

\[ a = \omega^2 \times r \]

where:
- \( \omega \) is the angular speed in radians per second.
- \( r \) is the radius of the circular path.

First, convert the angular speed from revolutions per second to radians per second:

\[ \omega = 5.0 \, \text{rev/s} \times 2\pi \, \text{rad/rev} = 10\pi \, \text{rad/s} \]

Now, use the formula to calculate the acceleration:

\[ a = (10\pi)^2 \times 0.15 \]

\[ a = 100\pi^2 \times 0.15 \]

\[ a ≈ 148 \, \text{m/s}^2 \]

Therefore, the correct answer is 148 m/s².
Transcribed Image Text:**Problem Statement:** A particle moves in a circular path of radius 0.15 m with a constant angular speed of 5.0 revolutions per second. The acceleration of the particle is: - ○ 986 m/s² - ○ 1600 m/s² - ○ 0.31 m/s² - ○ 7.5 m/s² - ○ 148 m/s² **Explanation:** To find the acceleration of the particle moving in a circular path, we use the formula for centripetal acceleration: \[ a = \omega^2 \times r \] where: - \( \omega \) is the angular speed in radians per second. - \( r \) is the radius of the circular path. First, convert the angular speed from revolutions per second to radians per second: \[ \omega = 5.0 \, \text{rev/s} \times 2\pi \, \text{rad/rev} = 10\pi \, \text{rad/s} \] Now, use the formula to calculate the acceleration: \[ a = (10\pi)^2 \times 0.15 \] \[ a = 100\pi^2 \times 0.15 \] \[ a ≈ 148 \, \text{m/s}^2 \] Therefore, the correct answer is 148 m/s².
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