A particle moves along the x axis. It is initially at the position 0.270 m, moving with velocity 0.210 m/s and acceleration-0.280 m/s2. Suppose it moves with constant acceleration for 4.50 s.(a) Find its position at the end of this time interval.-1.620(b) Find its velocity at the end of this time interval.-1.05m/sNext, assume it moves with simple harmonic motion for 4.50 s and x = 0 is its equilibrium position. (Assume that the velocity andacceleration is the same as in parts (a) and (b).)(C) Find its position at the end of this time interval.-0.122Your response differs from the correct answer by more than 10%. Double check your calculations. m(d) Find its velocity at the end of this time interval.m/s

Given,The position of the particle, x(0) = 0.270 mThe particle is moving with velocity, v(0)= 0.210…

Answered: A particle moves along the x axis. It…

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