A particle moves along the x-axis with an initial velocity v = 50 m/s at the origin when t = 0. For the first 4 seconds it has no acceleration, and thereafter it is acted on by a retarding force which gives it a constant acceleration a, = -10 m/s? . Calculate the velocity and the x-coordinate of the particle for the conditions of t = 8 s and t = 12 s and find the maximum positive x-coordinate reached by the particle. or =, + at Solve the problem using the equations of constant acceleration - v + 2a(s - 5,) +a +s=s 10

A particle moves along the x-axis with an initial velocity v = 50 m/s at the origin when t = 0. For the first 4 seconds it has no acceleration, and thereafter it is acted on by a retarding force which gives it a constant acceleration a, = -10 m/s? . Calculate the velocity and the x-coordinate of the particle for the conditions of t = 8 s and t = 12 s and find the maximum positive x-coordinate reached by the particle. or =, + at Solve the problem using the equations of constant acceleration - v + 2a(s - 5,) +a +s=s 10

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: ( The internal moment fund M(x) = ¹/x - 1x² Determine the location of (m) Determine the magnitude…

A: Answer : Data provided : The train is Parked on the Simply supported bridge. Modulus of elasticity…

Q: 3. 12-75 A particle travels along the circular path x 2 + i = r 2. If the y component of the…

Q: UARM2. A motorcycle is moving with uniform acceleration. After traveling for 3 seconds, it is found…

A: Step 1:Step 2: Step 3: Step 4:

Q: The velocity of the particle that travels along a straight line is v = (12 – 3t?)m/s, where t is in…

Q: Replace the forces system shown in figure (2) by an equivalent force acting at point A and a couple…

Q: 3. If the body is accelerating, it may be necessary to draw its free-body diagram and apply the…

A: We are authorized to answer one question at a time since you have not mentioned which question you…

Q: 4. A particle starts from rest at x = -2 m and moves along the x-axis with the velocity history…

A: - Acceleration of particle can be calculated by determining the slope of particle under velocity…

Q: The rotor of an electric motor has an angular velocity of 4500 rpm when the load and power are cut…

A: Given data: when θ=0angular velocity of the electric motor=4500 rpmweight of the rotor…

Q: The rotor of an electric motor has an angular velocity of 3600 rpm when the load and power are cut…

A: Calculate the initial angular velocity The final velocity is zero as the system comes to rest…

Q: lock when it is rest at t=0. De lacement to be

Q: A thin, uniform 3.90 kg bar, 80.0 cm long, has very small 2.50 kg balls glued on at either end…

A: Step 1: Step 2:Step 3: Step 4:

Q: Example A particle moves in the X-Y plane with a constant acceleration of 1.5 m/s² in the direction…

A: Given- constant acceleration a=1.5 m/s2angle=37oat t=0; velocity u=8.0 m/sVelocity and position of…

Q: 2. Analysis of Pendulum Motion a) The simple pendulum shown has a mass of 45g attached to a thread…

A: Given data,fig is given the mass =45glength=0.5mthe initial displacement=FIND a)The maximum speed of…

Question

Sample problem 2/2
A particle moves along the x-axis with an initial velocity v, =
50 m/s at the origin when t = 0. For the first 4 seconds it has no
acceleration, and thereafter it is acted on by a retarding force
which gives it a constant acceleration a, = -10 m/s?. Calculate
the velocity and the x-coordinate of the particle for the
conditions of t = 8 s and t = 12 s and find the maximum positive
x-coordinate reached by the particle.
Solve the problem
using the equations
of constant
acceleration
2- v + 2a(s - s,)
or s-s, +t

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Q1/ Two particles have a mass of 8 kg and 10 kg, respectively. If they are 800 mm apart, determine the force of gravity acting between them. Compare this result with the weight of each particle. (the universal constant of gravitation (G)= 6.673 * 10-11 m/(kg/s) )) Q2/ Two forces act on the hook. Determine the magnitude and the direction of the resultant force. 30° 0.2 KN 40° 400 N
The acceleration of a particle along a straight line is defined by a = (2t – 9)m/s², where t is in seconds. At t = 0, s = 1 m and v = 10 m/s. When t = 9 s, determine (a) the particle's position, (b) the total distance traveled, and (c) the velocity. Rectilinear Kinematics Show complete solution Answers: (a) s = - 30.5 m, (b) STot (c) 56.0 m, v = 10 m/s
Max launches a ball into a ballistic pendulum that has a length R = 0.600m and reaches a maximum angle of 20°. The mass of the ball m = 40.0g and the mass of the pendulum M = 200g. Speed of the ball before the collision is 6.00 m a) (2p) Use the equation given in the lab instructions to calculate the velocity of the pendulum right after the collision with the ball using angle and length of the pendulum. Show work!
Dynamic of rigid bodies
O Macmillan Learning A motorized wheel is spinning with a rotational velocity of wo = 1.81 rad/s. At t = 0 s, the operator switches the wheel to a higher speed setting. The rotational velocity of the wheel at all subsequent times is given by w (t) = woarctan (c + bt²) where c = 1.5574 and b = 6.09 s-². At what time tamax is the rotational acceleration at a maximum? tamax = a₁ = What is the maximum tangential acceleration a, of a point on the wheel a distance R = 1.29 m from its center? 0.358 Incorrect a = 0.126 Incorrect What is the magnitude of the total acceleration of this point? 239.4 Incorrect Attem m/s² ms m/s2
Dynamics of rigid bodies -COMPLETE SOLUTION! -Final answer should only be in numerical value.
11.13 The acceleration of a particle is defined by the relation a = A 6, where A is a constant. At t = 0, the particle starts at x = 8 m with E = 0. Knowing that at t = 1 s, v = 30 m/s, determine (a) the times at which the velocity is zero, (b) the total distance traveled by the particle when t = 5 s. 11.14 It is known that from t = 2 s to t = 10 s the acceleration of a particle is inversely proportional to the cube of the time t. When i = 2 s, v = -15 m/s, and when t = 10 s, v = 0.36 m/s. Knowing that the particle is twice as far from the origin when t = 2 s as it is when t 10 s, determine (a) the position of the particle when t = 2 s and when t = 10 s, (b) the total distance traveled by the particle from t = 2 s to t = 10 s. 11.15 The acceleration of a particle is defined by the relation a = -k/x. It has been experimentally determined that v = 15 ft/s when x = 0.6 ft and that v = 9 ft/s when x = 1.2 ft. Determine (a) the velocity of the particle when x = 1.5 ft, (b) the position of…
Problem 13.97 The particle has a mass of 0.8 kg and is confined to move along the smooth horizontal slot due to the rotation of the arm OA. (Figure 1) Figure 1 of 1 6=2 rad/s- 0 A 0.5 m Part A Determine the force of the rod on the particle and the normal force of the slot on the particle when 0 = 25°. The arm has an angular acceleration of 0 = 4 rad/s² and 0 = 2rad/s at this instant. Assume the particle contacts only one side of the slot at any instant. Express your answers using three significant figures separated by a comma. F. N = Submit ■ 7 ΑΣΦ ↓↑ vec My Answers Give Up ? Provide Feedback N Continue
At time t = 17 s, the velocity of a particle moving in the x-y plane is v = 0.14i + 2.92j m/s. By time t = 17.13 s, its velocity has become 0.01i + 2.82j m/s. Determine the magnitude day of its average acceleration during this interval and the angle made by the average acceleration with the positive x-axis. The angle is measured counterclockwise from the positive x-axis. Answers: dav = 0= i i m/s²
QUESTION 4: Made of a smooth material and a beam of constant cross section with two springs at ends A and B is supported. Both springs as constant k given. Any object on the beam vertical oscillation period 0.83 seconds. An object with a mass of 50 kg vertical oscillation when placed in the center period increases to 1.52 seconds. Both the stiffness of the spring and the mass of the beam Calculate.
A particle moves along a straight line so that:s = 3t3– 4t2Where “s” is in meters and “t” in minutes. Determine the velocity and acceleration when:t = 1 min; t = 2 min
A particle moves along a straight line such that its position is defined by s= (t 2 - 6t + 5) m. Determine the average velocity of the particle when t = 6 s