A particle moves along the x-axis so that at any time t, t 2 0, its acceleration is a(t) = -4 sin(2r). If the velocity of the particle at r = 0 is v(0) = 7 and its position at t = 0 is x(0) = 0, then its position at time / is x(t) = %3D %3D (A) sin(2t) +5t (B) sin(2r) +7t (C) sin(2t) + 9t (D) 16 sin(2r) + 7t
A particle moves along the x-axis so that at any time t, t 2 0, its acceleration is a(t) = -4 sin(2r). If the velocity of the particle at r = 0 is v(0) = 7 and its position at t = 0 is x(0) = 0, then its position at time / is x(t) = %3D %3D (A) sin(2t) +5t (B) sin(2r) +7t (C) sin(2t) + 9t (D) 16 sin(2r) + 7t
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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![A particle moves along the x-axis so that at any time r, t 2 0, its acceleration is a) =-4 sin(2r). If the
velocity of the particle at r= 0 is v(0) = 7 and its position at t= 0 is x(0) = 0, then its position at time r
is x(t) =
%3D
(A) sin(2t) + 5z
(B) sin(2r) + 7t
(C) sin(2r) + 9r
(D) 16sin(2r) + 7r](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2dde0a01-d978-4d5c-9c9c-f88afb02417c%2F24e540ed-e07d-4871-a49b-c9d18ec88aa3%2Fhhyamgj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A particle moves along the x-axis so that at any time r, t 2 0, its acceleration is a) =-4 sin(2r). If the
velocity of the particle at r= 0 is v(0) = 7 and its position at t= 0 is x(0) = 0, then its position at time r
is x(t) =
%3D
(A) sin(2t) + 5z
(B) sin(2r) + 7t
(C) sin(2r) + 9r
(D) 16sin(2r) + 7r
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