A particle moves along a straight line such that its acceleration is a = (42 - 2) m/s? where t is in seconds. When t = 0, the particle is located 2m to the left of the origin, and t = 2s, it is 20m to the left of the origin. Determine the position of the particle when t = 4
1. A particle moves along a straight line such that its acceleration is a = (42 - 2) m/s?
where t is in seconds. When t = 0, the particle is located 2m to the left of the origin,
and t = 2s, it is 20m to the left of the origin. Determine the position of the particle
when t = 4 s.
2. A particle is moving along a straight line with the acceleration a =12t - 3t2 ft/52,
where t is in seconds. Determine the velocity and the position of the particle as a
function of time. When t = 0, v = 0 and s = 15 ft.
3. A ball is released from the bottom of an elevator which is travelling upward with a
velocity of 6 m/s. The ball strikes the bottom of the elevator shaft in elevator shaft in
3s. Determine the height of the elevator from the bottom of the shaft to the instant
the ball is released, and find the velocity of the ball when it strike the bottom of the
shaft.
4. A particle moving along a straight line is subjected to a deceleration a =
-20m/52
where v is in m/s. If it has a velocity v = 8 m/s s = 10 m when t = 0, determine its
velocity.
5. The position of the particle is given by s=(2t^2- 8t + 6) m, where t is in seconds.
Determine the time when the velocity of the particle is zero, and the total distance travelled
by the particle when t = 3 s.
6. A particle travels along a straight line with an acceleration of a = (10 - 0.2s) m/s3, where s is
measured in meters. Determine the velocity of the particle when s = 10 m if v = 5 m/s at s = 0.
7.Two particles A and B start from rest at the origin s = 0 and move along a straight line such
that a = (6t - 3) ft/s? and ag = (12t2 - 8) ft/s?, where t is in seconds. Determine the distance
between them when t = 4 s and the total distance each has travelled in t = 4 s.
8.When a particle is projected vertically upwards with an initial velocity of Vo, it experiences anacceleration a= -(g+kv?), where g is the acceleration due to gravity, k is a constant and v is
the velocity of the particle. Determine the maximum height reached by the particle.
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