A particle moves along a straight line and its position at time t is given by s(t) = 2t³ - 24t² + 42t where s is measured in feet and t in seconds. Find the velocity (in ft/sec) of the particle at time t = 0: Answer: The particle stops moving (i.e. is in a rest) twice, once when t = A and again when t = B where A< B. Determine A and B. A = B = What is the position of the particle at time 16? Answer: Finally, what is the total distance the particle travels between time 0 and time 16? Answer:

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