(✰✰✰✰) A particle moves along a line. At time t (in seconds), the particle's velocity is v(t) = -t² + 5t − 6 (in m/s). Find the particle's net displacement and total distance traveled over the time interval [0, 5].

icon
Related questions
Question

Needs Complete typed solution with 100 % accuracy.                  

(★★☆☆) A particle moves along a line. At time t (in seconds), the particle's velocity is v(t) = −t² + 5t − 6
(in m/s). Find the particle's net displacement and total distance traveled over the time interval [0, 5].
Net displacement = (-5^3/3+5/2(5^2)-6(5))-(-0^3/3+5/2(0^2) (m)
Total distance traveled = -14/3-1/6+4/3
(m)
To understand the terms "net displacement" and "total distance travelled," imagine a particle that moves
from x = 0 to x = 2, then back to x = 1. Its net displacement is 1, since it started at position 0 and ended
at position 1. Its total distance travelled is 3, since it moved 3 units all together.
Transcribed Image Text:(★★☆☆) A particle moves along a line. At time t (in seconds), the particle's velocity is v(t) = −t² + 5t − 6 (in m/s). Find the particle's net displacement and total distance traveled over the time interval [0, 5]. Net displacement = (-5^3/3+5/2(5^2)-6(5))-(-0^3/3+5/2(0^2) (m) Total distance traveled = -14/3-1/6+4/3 (m) To understand the terms "net displacement" and "total distance travelled," imagine a particle that moves from x = 0 to x = 2, then back to x = 1. Its net displacement is 1, since it started at position 0 and ended at position 1. Its total distance travelled is 3, since it moved 3 units all together.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 3 images

Blurred answer