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A particle moves along a curve so that at any time t > 0, its x- 3 coordinate is given by x (t) = t³ - 4 and its y-coordinate is given by y(t) = 2t + 5. An equation of the tangent line to the curve at t= 1 is 2 ○ (A) y-7== (x+3) 3 3 O (B) y-7== (x+3) 2 O (C) y-7= 2(x+3) O (D) y-7= 3(x+3)

A particle moves along a curve so that at any time t > 0, its x- 3 coordinate is given by x (t) = t³ - 4 and its y-coordinate is given by y(t) = 2t + 5. An equation of the tangent line to the curve at t= 1 is 2 ○ (A) y-7== (x+3) 3 3 O (B) y-7== (x+3) 2 O (C) y-7= 2(x+3) O (D) y-7= 3(x+3)

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A particle moves along a curve so that at any time t > 0, its x- coordinate is given by x (t) = t³ - 4 and its y-coordinate is given by y(t) = 2t + 5. An equation of the tangent line to the curve at t= 1 is 2 O (A) y-7== (x+3) ○ (B) y- 7 = ²2/(x 3 = (x+3) O (C) y-7= 2(x+3) O (D) y-7= 3(x+3)
Transcribed Image Text:A particle moves along a curve so that at any time t > 0, its x- coordinate is given by x (t) = t³ - 4 and its y-coordinate is given by y(t) = 2t + 5. An equation of the tangent line to the curve at t= 1 is 2 O (A) y-7== (x+3) ○ (B) y- 7 = ²2/(x 3 = (x+3) O (C) y-7= 2(x+3) O (D) y-7= 3(x+3)
20. Using the substitution u = x², © 2 (A) / Se 1 -2 (B) 2 e" du 25₁ 1 (C) e" du •√₂ 1 e" du √₂ (D) 2 e du 1 √√2 te+² dx is equal to which of the following? 1
Transcribed Image Text:20. Using the substitution u = x², © 2 (A) / Se 1 -2 (B) 2 e" du 25₁ 1 (C) e" du •√₂ 1 e" du √₂ (D) 2 e du 1 √√2 te+² dx is equal to which of the following? 1
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