A particle moves along a circular path of radius 5 ft. If its position is 0 = (e0.5t) rad/s, where t is in seconds, determine the magnitude of the particle's acceleration when 0 = 90°.
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- A golf ball is driven with the initial conditions shown in the figure. If the wind imparts a constant horizontal deceleration of 3.9 ft/sec2, determine the values of r, r˙, r¨, θ, θ˙, and θ¨ when t = 1.18 sec. Take the r-coordinate to be measured from the origin.You can use the formula for centripetal acceleration OR You have to calculate the average acceleration directly from the definition, a = delta v / delta t. You have to first get a_x by using the velocity's initial and final x components, do a_y from the y components, and then use the Pythagorean formula to get the magnitude of the acceleration vector.At t1 = 3.00 s, the acceleration of a particle moving at constant speed in counterclockwise circular motion is an = (3.00 m/s?)ì + (6.00 m/s) ^ At t2 = 7.00 s (less than one period later), the acceleration is a2 = (6.00 m/s3)ì - (3.00 m/s2)î The period is more than 4.00 s. What is the radius of the circle?
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