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A particle moves according to a law of motion s = f(t) = t³ – 2t2 – 5t + 10, where tis measured in seconds and s in feet. Use it to answer the following questions. (For some answers you have to input numbers, for others to choose either A, or B, or C, or D from the list below the questions.) (i) The velocity as a function of t is (ii) The acceleration as a function of t is (iii) The acceleration after 2 seconds is ft/sec?. (iv) The acceleration when the velocity is 0 ft/sec?. (v) The acceleration when the velocity is –5 ft/sec?.

A particle moves according to a law of motion s = f(t) = t³ – 2t2 – 5t + 10, where tis measured in seconds and s in feet. Use it to answer the following questions. (For some answers you have to input numbers, for others to choose either A, or B, or C, or D from the list below the questions.) (i) The velocity as a function of t is (ii) The acceleration as a function of t is (iii) The acceleration after 2 seconds is ft/sec?. (iv) The acceleration when the velocity is 0 ft/sec?. (v) The acceleration when the velocity is –5 ft/sec?.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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A particle moves according to a law of motion s = f(t) = t3 – 2t? – 5t + 10, where t is measured in seconds and s in feet. Use it to answer the following questions. (For some answers you have to input numbers, for others to choose either A, or B, or C, or D from the list below the questions.) (i) The velocity as a function of t is (ii) The acceleration as a function of t is (iii) The acceleration after 2 seconds is ft/sec?. (iv) The acceleration when the velocity is 0 ft/sec?. (v) The acceleration when the velocity is –5 ft/sec². A) v(t) = ť² – 4t – 5 В) о(t) — 2t — 4 С) а (t) — t? —4t — 5 D) a(t) = 2t – 4
Transcribed Image Text:A particle moves according to a law of motion s = f(t) = t3 – 2t? – 5t + 10, where t is measured in seconds and s in feet. Use it to answer the following questions. (For some answers you have to input numbers, for others to choose either A, or B, or C, or D from the list below the questions.) (i) The velocity as a function of t is (ii) The acceleration as a function of t is (iii) The acceleration after 2 seconds is ft/sec?. (iv) The acceleration when the velocity is 0 ft/sec?. (v) The acceleration when the velocity is –5 ft/sec². A) v(t) = ť² – 4t – 5 В) о(t) — 2t — 4 С) а (t) — t? —4t — 5 D) a(t) = 2t – 4
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