Parts A-C only A particle is moving is such a way that its position after time t is described by the vectore-twhere t is measured in s. The particle has a mass of 2.0 kg.(a) What is the position of the particle at t = 1.0 s?(b) How far is the particle from the origin at t = 1.0 s?(c) What is the velocity of the particle at t = 1.0 s?(d) What is the speed of the particle at t = 1.0 s?(e) What is the momentum of the particle at t = 1.0 s?(f) What is the kinetic energy of the particle at t = 1.0 s?(g) What is the acceleration of the particle at t = 1.0 s?(h) What is the total force on the particle at t = 1.0 s?Report all numerical values in standard SI units.

For a particle located at x,y,z the distance from origin is given by, d=x2+y2+z2. The velocity is the time rate of change of position. v→=dr→dt.(a) The position vector at time t is, r→=[ti^+t-0.5t2j^+e-tk^] m At t = 1s the position is, r→=[1i^+1-0.5×12j^+e-1k^] m r→=[1i^+0.5j^+e-1k^] m The position of the particle at t = 1s is, r→=[1i^+0.5j^+e-1k^] m. (b) The distance from the origin is, d=12+0.52+e-12 m=1.177 m. The particle is at a distance of 1.177 m from the origin. (c) The velocity v→=dr→dt=ddtti^+t-0.5t2j^+e-tk^ v→=1i^+1-tj^+-e-tk^ m/s At t = 1s, v→=1i^+1-1j^+-e-1k^ m/s = (1i^+0j^-0.3678) m/s The velocity of the particle at t = 1s is, v→=(1i^+0j^-0.3678) m/s.