A particle is moving along a curve so that its position at time t≥ 0 is given by (x(t),y(t)). dx At time t= 0, the particle is at position (-4,2). It is known that - dt dy = 2t + 3 and = dt a. Find an equation of the tangent line to the path of the particle at t = 0. b. Find the acceleration vector. What is the acceleration vector at time t = 1? c. Find the speed of the particle at time t = 0. d. Find all times t for which the particle is in the first quadrant. 3t 18e ³t

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