A particle has zero velocity initially (i.e., at time t = 0) and its acceleration at 1 seconds is a(t) = 72t – 4t³ meters-per- second per second. During the time interval [5, 8] seconds, (i) the average acceleration of this particle is -689 (ii) the average speed of this particle is meters-per-second per second meters-per-second.

Q: A person dives from a 30-foot platform with an initial upward velocity of 5 ft/s. The diver’s height…

A:

Q: 4) How quickly is an airplane's elevation currently rising if its height (in feet) as a function of…

A: We need to find rate of change of elevation or rate of change of height when t = 4 sec Hence we will…

Q: Suppose an object is moving along a line such that the acceleration after t seconds is 6t -8t…

A:

Q: A mountain climber uses the model T = 20 – 10h | to estimate the temperature T (in °C) at elevation…

A: T=20-10h a). When h=0, T=20-100=20 When h=1, T=20-101=10 When h=2, T=20-102=0 When h=3, T=20-103=-10…

Q: (3) The distance of a particle from a point O at time t seconds is given by s = 2t³ - 27t² + 108t -…

A: Given : s=2t3-27t2+108t-84   ,   t≥0 To find : (a) velocity (b) Acceleration (c) Time when velocity…

Q: I got to the step where I have (5h/h-1)/h. I think I can multimply (5h/h-1) by (h/1). This results…

A: We have to find actual expression for the given expression.

Q: 4) Suppose that a baseball is tossed straight upward and its height (in feet) as a function of a…

A: (a) Instantaneous velocity and acceleration The height y  of the baseball as a function of time t…