Answered: A particle has an initial velocity v,…

A particle has an initial velocity v, at angle ø with respect to the horizontal. The maximum height it can reach is when A) ø = 30° Β) φ= 450 C) ø= 60° D) ø= 90°

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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F1 = 5 kN F2 13 kN 0 = 45° B = 60° F3 = 4 kN A 4 m 3. 8 m F4 = 22 kN E Ja = 30° F5 = 4 k 1] What is the resultant moment of the five forces acting on the rod about point A? a) 3.5 kN.m b) 16.2 kN.m c) 20.2 kN.m d) 11.5 kN.m e) 33.1 kN.m f) 8.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point C? a) 47.5 kN.m b) 55.5 kN.m c) 12.2 kN.m d) 61.9 kN.m e) 79.1 kN.m f) 44.1 kN.m 3] What is the moment of the force F1 about point E? a) – 22.8 kN.m b) - 49.5 kN.m с)- 55.9 kN.m d) - 9.1 kN.m e) - 12.7 kN.m f) - 25.9 kN.m 4] What is the moment of the force F2 about point D? a) 40.5 kN.m b) 71.5 kN.m c) 14.2 kN.m d) 64.5 kN.m e) 56.1 kN.m f) 39.1 kN.m 5] What is the moment of the force F5 about point A? а) - 17.8 kN.m b) - 4.8 kN.m c) - 12.9 kN.m d) - 8.1 kN.m e) - 32.7 kN.m f) - 2.9 kN.m D.
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11. A particle moving along a straight line has its position s in meters at any time t in seconds given by s=t' + 4t. When will the velocity be numerically equal to its acceleration? A) t= 3.67 s B) t = 1.89 s C) t= 2.50 s D) t= 1.33 s
D. C. F3 B. F4 Consider the following values: FS a-25 m; b 5 m; c 25 m; d-5 m; F1-7 kN; F2 8 kN; F3 - 9 kN; F4 -10 kN; F5 11 kN; 1] What is the resultant moment of the five forces acting on the rod about point A? a)-158 kN.m c) 146 kN.m d) - 103 kN.m e) 241 kN.m NA ILI -G 21 What is the resultant moment of the five forces acting on the rod about point B? a) 98.8 kN.m b)-291.7 kN.m c) 311.6 kN.m d)-264.6 kN.m e) 354.2 kN.m 0-242.51 31 What is the resultant moment of the five forces acting on the rod about point C? a) 86.7 kN.m c) 14.6 kN.m d)-272.1 kN.m e) 174.1 kN.m f-315.3 ka 41 What is the resultant moment of the five forces acting on the rod about point D? a)-117.8 kN.m b) 82.7 kN.m c) 121.9 kN.m d)-259.9 kN.m 51 What is the moment of the force F2 about point E? Activa
* llı. Classroom A docs.google.com Test 2/ Course 1/ Mechanics / Evening مطلوب Untitled Section F1 = 5 kN F2 = 13 kN 0-45° A - 60 B F3 = 4 kN A 2 m 7 m F4 = 22 kN ID Ja= 30 FS = 4 kN 1] What is the resultant moment of the five forces acting on the rod about point A? a) 11.1 kN.m b) 9.3 kN.m c) 16.2 kN.m d) 18.5 kN.m e) 6.6 kN.m f) 2.9 kN.m 2] What is the resultant moment of the five forces acting on the rod about point C? a) 65.1 kN.m b) 74.3 kN.m c) 19.2 kN.m d) 26.5 kN.m e) 42.9 kN.m ) 55.1 kN.m 3] What is the moment of the force F1 about point E? а)- 19.3 kN.m b) -17.1 kN.m с) - 6.3 kN.m d) - 22.1 kN.m e) - 39.7 kN.m ) - 45.9 kN.m 4] What is the moment of the force F2 about point D? a) 17.1 kN.m b) 48.3 kN.m c) 6.2 kN.m d) 14.5 kN.m e) 42.1 kN.m f) 23.1 kN.m 5] What is the moment of the force F5 about point A? a) - 19.9 kN.m b) -18.1 kN.m c) - 8.3 kN.m d) - 15.1 kN.m e) - 2.7 kN.m f) - 6.8 kN.m * ;The answer is [1
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A=Ai+Aj |4=√√A,²+A₂² Problem 1 (a). b) c) d) Ya 30° 60° F, 20 kN F, X 16 KN Three forces, F1, F2, and F3, act on a bracket. The magnitude of F3 is 10 kN. If the resultant force, R acts along the x- direction (horizontal), determine the direction angles of the Cartesian force vector, F3. Determine the magnitude of the resultant force, R. A₁ = 4 cos a A, = 4|cos B cos² a + cos² B=1 Determine the FORCE vector, F3 FORCE vector, F1 =__ FORCE vector, F2 = Determine the direction angles, a and ß of the force, F3 [HINT: find 3 first] FORCE vector, F3=_ Determine resultant force vector, R FORCE vector, R= B= α= kN kN O O kN KN
Find the wrong statement A)Shear stress is zero in hydrostatics B)Pelton turbine is an impulse turbine C)None D)For flow over sphere (external flow), if the Reynolds number is greater than 4400, then flow is turbulent E)Turbulent flow is a chaotic and random motion of fluid particles
Problem #2) A 155.3 slg SUV plows into the rear of a 68.32 slg sportscar. The collision was perfectly plastic; there was no bounce observed. Just before the collision the SUV was traveling at 29.3 ft/s, and the sportscar was stationary. The entire collision takes 0.3 seconds. a) What are the two vehicles' speeds, v'suv and v'sc, immediately following the collision? b) What average accelerations, asuv and asc, do the two vehicles experience? lost m = 155.3519 Suv m = M 68.32 sig sp V29.3 ft/s Suv V = 0 ft/s Sp t = 0.35 plastic: energy e=0
4.) A particle must execute curvlinear motion in order for it to have angular momentum about a point. A.) True B.) False 5.) For the motion of a rigid body to be a translation, the center mass of the body must move along a straight line. A.) True B.) False
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