A particle accelerator is used to accelerate particles... (obviously right?). a) Draw a diagram that would represent a proton, starting from rest, and passing between two plates with a potential difference of 5.3 z 10° V, and the plates separated 12cm apart. (Include SIGNS on plates), accelerating. b) How fast would the proton be traveling as it goes from one side to the other? c) What would be the magnitude of the electric field strength? d) What would be the acceleration of the proton?

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Please answer question and just send me the paper solutions asap dont type the answer question 13abcd and use law conservation of energy if need and use this formula 20mins only
Question 13
A particle accelerator is used to accelerate particles... (obviously right?).
a) Draw a diagram that would represent a proton, starting from rest, and passing between two plates with a potential difference of
5.3z 10 V and the plates separated 12cm apart. (Include SIGNS on plates), accelerating.
b) How fast would the proton be traveling as it goes from one side to the other?
c) What would be the magnitude of the electric field strength?
d) What would be the acceleration of the proton?
18°C
Transcribed Image Text:Question 13 A particle accelerator is used to accelerate particles... (obviously right?). a) Draw a diagram that would represent a proton, starting from rest, and passing between two plates with a potential difference of 5.3z 10 V and the plates separated 12cm apart. (Include SIGNS on plates), accelerating. b) How fast would the proton be traveling as it goes from one side to the other? c) What would be the magnitude of the electric field strength? d) What would be the acceleration of the proton? 18°C
GMm
F, =
mearth = 5.97 x 1024kg
mmoon = 7.34 x 1022kg
%3D
Nm?
G = 6.67x10-11
kg?
v²
ac =
re = 6378 km
Tmoon = 1737 A bm
ac = 4n?rf2
472r
ac =
kq,92
Fe =
mproton = 1.67 x 10-27kg
9.11 x 10-31kg
melectron
%3D
Nm2
k = 8.99x10°
C2
Telectron/proton
= ±1.60x10-19C
Fe = qɛ
%3D
AE = -W = -F,Ad=-qeAd
ΔΕ,
AV =
b.
kq
E =
AV
Ad
Fmagnetic = qvBsine
m. 9.11 10-31kg
q3±1.60 10-19C
1
E =mv?
Ee = qAV
%3D
m, = 1.67 10-27kg
F = qe
v2
ac =
r.
Transcribed Image Text:GMm F, = mearth = 5.97 x 1024kg mmoon = 7.34 x 1022kg %3D Nm? G = 6.67x10-11 kg? v² ac = re = 6378 km Tmoon = 1737 A bm ac = 4n?rf2 472r ac = kq,92 Fe = mproton = 1.67 x 10-27kg 9.11 x 10-31kg melectron %3D Nm2 k = 8.99x10° C2 Telectron/proton = ±1.60x10-19C Fe = qɛ %3D AE = -W = -F,Ad=-qeAd ΔΕ, AV = b. kq E = AV Ad Fmagnetic = qvBsine m. 9.11 10-31kg q3±1.60 10-19C 1 E =mv? Ee = qAV %3D m, = 1.67 10-27kg F = qe v2 ac = r.
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