A parcel is connected to a flying drone as illustrated above. Note that the coordinate system is given with +y pointed in the upwards direction. Holding the parcel, the drone takes off moving straight up with a velocity of 8.40. m/s. Note that, as usual, y = 0 at the ground. After 8.00 s, the drone accidentally releases the parcel! The parcel is in “freefall” immediately after it is released, as defined in Lecture 7. Assume that the magnitude of the acceleration, g = 9.81 m/s2 , and that the drone continues with the same velocity after releasing the parcel. Ignore the effects of air-resistance a) What is the acceleration of the drone as it travels upwards? b) What is the velocity of the parcel immediately after it is released? c) What is the acceleration of the parcel immediately after it is released? (Remember acceleration is a vector and the sign is important (i.e. “+” for pointing up, or “-” for pointing down. d) What is the velocity and acceleration of the parcel when it reaches its maximum height? e) What is the maximum height reached by the parcel? f) How far apart are the drone and parcel when the parcel reaches its maximum height? g) At what time(s) after release does the parcel have a speed of 4.20 m/s? Hint: there are two different times when the parcel has this speed. h) At what height does the parcel have a velocity of -8.40 m/s? (Hint: use symmetry to solve) i) What is the velocity of the parcel right before it slams into the ground? j) What is the average velocity of the parcel between the time it is released and the time it slams into the ground? k) What is the speed of the parcel right before it slams into the ground, in units of km/hour? (note you only need to convert the magnitude of your answer from part (i) to units of km/hr.)
A parcel is connected to a flying drone as illustrated above. Note that the coordinate system is given
with +y pointed in the upwards direction. Holding the parcel, the drone takes off moving straight up
with a velocity of 8.40. m/s. Note that, as usual, y = 0 at the ground.
After 8.00 s, the drone accidentally releases the parcel! The parcel is in “freefall” immediately after it is
released, as defined in Lecture 7. Assume that the magnitude of the acceleration, g = 9.81 m/s2
, and that
the drone continues with the same velocity after releasing the parcel. Ignore the effects of air-resistance
a) What is the acceleration of the drone as it travels upwards?
b) What is the velocity of the parcel immediately after it is released?
c) What is the acceleration of the parcel immediately after it is released? (Remember acceleration
is a vector and the sign is important (i.e. “+” for pointing up, or “-” for pointing down.
d) What is the velocity and acceleration of the parcel when it reaches its maximum height?
e) What is the maximum height reached by the parcel?
f) How far apart are the drone and parcel when the parcel reaches its maximum height?
g) At what time(s) after release does the parcel have a speed of 4.20 m/s? Hint: there are two
different times when the parcel has this speed.
h) At what height does the parcel have a velocity of -8.40 m/s? (Hint: use symmetry to solve)
i) What is the velocity of the parcel right before it slams into the ground?
j) What is the average velocity of the parcel between the time it is released and the time it slams
into the ground?
k) What is the speed of the parcel right before it slams into the ground, in units of km/hour? (note
you only need to convert the magnitude of your answer from part (i) to units of km/hr.)
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