A parallel plate capacitor with a value of 226 pF is made from two square plates with a side length of 40 mm and these two plates are separated by a dielectric material with a thickness of 500 µm. (i) (ii) Explain what the dielectric strength of a material is and state its units. Calculate the relative permittivity of the dielectric material.

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A parallel plate capacitor with a value of 226 pF is made from two square
plates with a side length of 40 mm and these two plates are separated by
a dielectric material with a thickness of 500 μm.
(i)
(ii)
(iii)
(iv)
Explain what the dielectric strength of a material is and state its
units.
Calculate the relative permittivity of the dielectric material.
If a voltage of 5 V is applied across the capacitor of part (i), what
is the energy stored in it and how much charge is stored on each
plate?
If the value of the capacitor has to increase by 40%, and the same
dielectric material with the same thickness is to be used, calculate
the length of the new square plate which has to be used to achieve
this increase.
Transcribed Image Text:A parallel plate capacitor with a value of 226 pF is made from two square plates with a side length of 40 mm and these two plates are separated by a dielectric material with a thickness of 500 μm. (i) (ii) (iii) (iv) Explain what the dielectric strength of a material is and state its units. Calculate the relative permittivity of the dielectric material. If a voltage of 5 V is applied across the capacitor of part (i), what is the energy stored in it and how much charge is stored on each plate? If the value of the capacitor has to increase by 40%, and the same dielectric material with the same thickness is to be used, calculate the length of the new square plate which has to be used to achieve this increase.
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