A parallel plate capacitor with a value of 226 pF is made from two squareplates with a side length of 40 mm and these two plates are separated bya dielectric material with a thickness of 500 μm.(i)(ii)(iii)(iv)Explain what the dielectric strength of a material is and state itsunits.Calculate the relative permittivity of the dielectric material.If a voltage of 5 V is applied across the capacitor of part (i), whatis the energy stored in it and how much charge is stored on eachplate?If the value of the capacitor has to increase by 40%, and the samedielectric material with the same thickness is to be used, calculatethe length of the new square plate which has to be used to achievethis increase.

Given,The capacitance of a parallel plate capacitor, C = 226 pFThe length of the side of the square…

A parallel plate capacitor with a value of 226 pF is made from two square plates with a side length of 40 mm and these two plates are separated by a dielectric material with a thickness of 500 µm. (i) (ii) Explain what the dielectric strength of a material is and state its units. Calculate the relative permittivity of the dielectric material.

A parallel plate capacitor with a value of 226 pF is made from two square plates with a side length of 40 mm and these two plates are separated by a dielectric material with a thickness of 500 µm. (i) (ii) Explain what the dielectric strength of a material is and state its units. Calculate the relative permittivity of the dielectric material.