A parallel-plate capacitor is constructed by filling the space between two square plates with a block of three dielectric materials, as shown in the figure below. You may assume that d. (a) Find an expression for the capacitance of the device in terms of the plate area A and d, . Kg, and Ky. (Use the following as necessary: K. Kge Kg, kga A and d.) (b) Calculate the capacitance using the values A 1.40 cm", d- 2.00 mm, K,- 4.90, K2 - 5.60, and - 2.40.
A parallel-plate capacitor is constructed by filling the space between two square plates with a block of three dielectric materials, as shown in the figure below. You may assume that d. (a) Find an expression for the capacitance of the device in terms of the plate area A and d, . Kg, and Ky. (Use the following as necessary: K. Kge Kg, kga A and d.) (b) Calculate the capacitance using the values A 1.40 cm", d- 2.00 mm, K,- 4.90, K2 - 5.60, and - 2.40.
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Transcribed Image Text:A parallel-plate capacitor is constructed by filling the space between two square plates with a block of three dielectric materials, as shown in the figure below. You may assume that d.
(a) Find an expression for the capacitance of the device in terms of the plate area A and d, K. kg. and y. (Use the following as necessary: K Kgr Kg, kg A and d.)
(b) Calculate the capacitance using the values A 1.40 cm", d- 2.00 mm, K,- 4.90, K2 - 5.60, and - 2.40.
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