A parallel plate capacitor has plates of area A = 5.50 x 10-² m² separated by distance d = 2.37 x 10-4 m. (The permittivity of free space is = 8.85 x 10-12 c²/(N m²).) |HINT (a) Calculate the capacitance (in F) if the space between the plates is filled with air. 2.05e-9 ✓ F What is the capacitance (in F) if the space is filled half with air and half with a dielectric of constant x = 2.30 as in figure (a), and figure (b)? (Hint: One of the capacitors is a parallel combination and the other is a series combination.) (b) figure (a) 2.85e-9 (c) figure (b) 1.90e-16 ✓ F X F A K b A 4
A parallel plate capacitor has plates of area A = 5.50 x 10-² m² separated by distance d = 2.37 x 10-4 m. (The permittivity of free space is = 8.85 x 10-12 c²/(N m²).) |HINT (a) Calculate the capacitance (in F) if the space between the plates is filled with air. 2.05e-9 ✓ F What is the capacitance (in F) if the space is filled half with air and half with a dielectric of constant x = 2.30 as in figure (a), and figure (b)? (Hint: One of the capacitors is a parallel combination and the other is a series combination.) (b) figure (a) 2.85e-9 (c) figure (b) 1.90e-16 ✓ F X F A K b A 4
College Physics
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ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:A parallel plate capacitor has plates of area \( A = 5.50 \times 10^{-2} \, \text{m}^2 \) separated by a distance \( d = 2.37 \times 10^{-4} \, \text{m} \). The permittivity of free space is \( \varepsilon_0 = 8.85 \times 10^{-12} \, \text{C}^2/(\text{N} \cdot \text{m}^2) \).
**(a)** Calculate the capacitance (in F) if the space between the plates is filled with air.
- **Answer:** \( 2.05 \times 10^{-9} \, \text{F} \) ✔️
**What is the capacitance (in F) if the space is filled half with air and half with a dielectric of constant \( \kappa = 2.30 \) as in figure (a), and figure (b)?**
(Hint: One of the capacitors is a parallel combination and the other is a series combination.)
- **(b) Figure (a):** \( 2.85 \times 10^{-9} \, \text{F} \)
- **(c) Figure (b):** \( 1.90 \times 10^{-16} \, \text{F} \) ❌
### Explanation of Figures
Figures (a) and (b) illustrate two scenarios with a parallel plate capacitor:
- **Figure (a):** Shows the capacitor with half of the region filled with a dielectric material having a dielectric constant \( \kappa = 2.30 \) and the other half filled with air. This setup leads to a parallel combination of capacitors.
- **Figure (b):** Displays the capacitor with a similar division between air and dielectric but arranged in a manner that leads to a series combination of capacitors.
The gray plates labeled \( A \) are the conducting plates, and the area between them is sectioned with the dielectric \( \kappa \) in yellow. The separation distance \( d \) is indicated between the plates.
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