(a) P(A N D) 1/14 (b) P(B N D) 3/35 (c) P(CN D) 3/8 (d) P(D) (e) Verify. P(A | D) = P(A N D) P(D) P(A) · P(D | A) P(A) · P(D | A) + P(B) · P(D | B) + P(C) · P(D | C) 1)•(C
(a) P(A N D) 1/14 (b) P(B N D) 3/35 (c) P(CN D) 3/8 (d) P(D) (e) Verify. P(A | D) = P(A N D) P(D) P(A) · P(D | A) P(A) · P(D | A) + P(B) · P(D | B) + P(C) · P(D | C) 1)•(C
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
Related questions
Question

Transcribed Image Text:Use this diagram to find the following probabilities.
(a) P(A N D)
1/14
(b) P(B N D)
3/35
(c)
P(C N D)
3/8
(d)
P(D)
(e) Verify.
P(A N D) -
P(D)
P(A) · P(D | A)
P(A) · P(D | A) + P(B) · P(D | B) + P(C) · P(D | C)
P(A | D) =
XC
||

Transcribed Image Text:The accompanying tree diagram represents a two-stage experiment.
D
1/2
A
1/2
1/7
-D°
D
1/5
3/7
-B
4/5
-D°
3/7
D
7/8
1/8
-D°
Use this diagram to find the following probabilities.
(a)
P(A N D)
1/14
(b)
P(B N D)
3/35
(c)
P(C N D)
3/8
Expert Solution

This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps with 2 images

Recommended textbooks for you

A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON


A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
