A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below. Fx (N) 4 3 2 - 2 4 6 8 10 12 14 16 18 20 x (m) (a) Find the work done by the force on the object as it moves from x = 0 to x = 5.00 m. 10 J (b) Find the work done by the force on the object as it moves from x = 5.00 m to x = 12.0 m. 21 X Your response differs from the correct answer by more than 10%. Double check your calculations. J (c) Find the work done by the force on the object as it moves from x = 12.0 m to x = 16.0 m. 12 X Your ro differs from the correct answer by more than 1096 Double check your calculations 1

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### Educational Content: Work and Kinetic Energy

#### Overview
An object of mass 3.00 kg is subject to a force \( F_x \) that varies with position, as shown in the figure below.

#### Graph Explanation
- **X-axis:** Represents position \( x \) in meters (m), ranging from 0 to 20 m.
- **Y-axis:** Represents force \( F_x \) in newtons (N), ranging from 0 to 6 N.
- The graph is a piecewise linear function with the following segments:
  - From \( x = 0 \) to \( x = 4 \), the force increases linearly from 0 N to 3 N.
  - From \( x = 4 \) to \( x = 12 \), the force remains constant at 3 N.
  - From \( x = 12 \) to \( x = 16 \), the force decreases linearly back to 0 N.
  - From \( x = 16 \) to \( x = 20 \), the force remains constant at 0 N.

#### Questions
(a) **Calculate the work done** by the force on the object as it moves from \( x = 0 \) to \( x = 5.00 \) m.
- **Answer:** 10 J ✓

(b) **Calculate the work done** by the force on the object as it moves from \( x = 5.00 \) m to \( x = 12.0 \) m.
- **Answer:** 21 J ✗  
  *Your response differs from the correct answer by more than 10%. Double check your calculations.*

(c) **Calculate the work done** by the force on the object as it moves from \( x = 12.0 \) m to \( x = 16.0 \) m.
- **Answer:** 12 J ✗  
  *Your response differs from the correct answer by more than 10%. Double check your calculations.*

(d) **If the object has a speed** of 0.400 m/s at \( x = 0 \), find its speed at \( x = 5.00 \) m and its speed at \( x = 16.0 \) m.
- Speed at \( x = 5.00 \) m: 2.62 m/s ✓
- Speed at \( x =
Transcribed Image Text:### Educational Content: Work and Kinetic Energy #### Overview An object of mass 3.00 kg is subject to a force \( F_x \) that varies with position, as shown in the figure below. #### Graph Explanation - **X-axis:** Represents position \( x \) in meters (m), ranging from 0 to 20 m. - **Y-axis:** Represents force \( F_x \) in newtons (N), ranging from 0 to 6 N. - The graph is a piecewise linear function with the following segments: - From \( x = 0 \) to \( x = 4 \), the force increases linearly from 0 N to 3 N. - From \( x = 4 \) to \( x = 12 \), the force remains constant at 3 N. - From \( x = 12 \) to \( x = 16 \), the force decreases linearly back to 0 N. - From \( x = 16 \) to \( x = 20 \), the force remains constant at 0 N. #### Questions (a) **Calculate the work done** by the force on the object as it moves from \( x = 0 \) to \( x = 5.00 \) m. - **Answer:** 10 J ✓ (b) **Calculate the work done** by the force on the object as it moves from \( x = 5.00 \) m to \( x = 12.0 \) m. - **Answer:** 21 J ✗ *Your response differs from the correct answer by more than 10%. Double check your calculations.* (c) **Calculate the work done** by the force on the object as it moves from \( x = 12.0 \) m to \( x = 16.0 \) m. - **Answer:** 12 J ✗ *Your response differs from the correct answer by more than 10%. Double check your calculations.* (d) **If the object has a speed** of 0.400 m/s at \( x = 0 \), find its speed at \( x = 5.00 \) m and its speed at \( x = 16.0 \) m. - Speed at \( x = 5.00 \) m: 2.62 m/s ✓ - Speed at \( x =
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