A object of mass 3.00 kg is subject to a force Fx that varies with position as in the figure below. Fx (N) 4 3 2 1 x (m) i (a) Find the work done by the force on the object as it moves from x = 0 to x = 4.00 m. 2 4 6 8 10 12 14 16 18 20

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**Transcription for Educational Website:**

An object of mass 3.00 kg is subject to a force \( F_x \) that varies with position, as shown in the figure below.

**Graph Description:**
- The y-axis represents the force \( F_x \) in Newtons (N), ranging from 0 to 4.
- The x-axis represents the position \( x \) in meters (m), ranging from 0 to 20.

**Force vs Position Graph:**
- From \( x = 0 \) to \( x = 2 \), the force linearly increases from 0 N to 2 N.
- From \( x = 2 \) to \( x = 4 \), the force remains constant at 2 N.
- From \( x = 4 \) to \( x = 10 \), the force gradually decreases to 1 N.
- From \( x = 10 \) to \( x = 17 \), the force decreases to 0 N.


**Questions:**

(a) Find the work done by the force on the object as it moves from \( x = 0 \) to \( x = 4.00 \, \text{m} \).

\[ \text{Answer: } \_\_\_\_ \, J \]

(b) Find the work done by the force on the object as it moves from \( x = 4.00 \, \text{m} \) to \( x = 10.0 \, \text{m} \).

\[ \text{Answer: } \_\_\_\_ \, J \]

(c) Find the work done by the force on the object as it moves from \( x = 10.0 \, \text{m} \) to \( x = 17.0 \, \text{m} \).

\[ \text{Answer: } \_\_\_\_ \, J \]

(d) If the object has a speed of \( 0.450 \, \text{m/s} \) at \( x = 0 \), find its speed at \( x = 4.00 \, \text{m} \) and its speed at \( x = 17.0 \, \text{m} \).

Speed at \( x = 4.00 \, \text{m} \): \[ \_\_\_\_ \
Transcribed Image Text:**Transcription for Educational Website:** An object of mass 3.00 kg is subject to a force \( F_x \) that varies with position, as shown in the figure below. **Graph Description:** - The y-axis represents the force \( F_x \) in Newtons (N), ranging from 0 to 4. - The x-axis represents the position \( x \) in meters (m), ranging from 0 to 20. **Force vs Position Graph:** - From \( x = 0 \) to \( x = 2 \), the force linearly increases from 0 N to 2 N. - From \( x = 2 \) to \( x = 4 \), the force remains constant at 2 N. - From \( x = 4 \) to \( x = 10 \), the force gradually decreases to 1 N. - From \( x = 10 \) to \( x = 17 \), the force decreases to 0 N. **Questions:** (a) Find the work done by the force on the object as it moves from \( x = 0 \) to \( x = 4.00 \, \text{m} \). \[ \text{Answer: } \_\_\_\_ \, J \] (b) Find the work done by the force on the object as it moves from \( x = 4.00 \, \text{m} \) to \( x = 10.0 \, \text{m} \). \[ \text{Answer: } \_\_\_\_ \, J \] (c) Find the work done by the force on the object as it moves from \( x = 10.0 \, \text{m} \) to \( x = 17.0 \, \text{m} \). \[ \text{Answer: } \_\_\_\_ \, J \] (d) If the object has a speed of \( 0.450 \, \text{m/s} \) at \( x = 0 \), find its speed at \( x = 4.00 \, \text{m} \) and its speed at \( x = 17.0 \, \text{m} \). Speed at \( x = 4.00 \, \text{m} \): \[ \_\_\_\_ \
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