A nylon string on a tennis racket is under a tension of 215 N. Part A If its diameter is 1.05 mm, by how much is it lengthened from its untensioned length of 30.0 cm ? Use ENylon = 5.00 × 10⁹ N/m². AL || V ΑΣΦ t
A nylon string on a tennis racket is under a tension of 215 N. Part A If its diameter is 1.05 mm, by how much is it lengthened from its untensioned length of 30.0 cm ? Use ENylon = 5.00 × 10⁹ N/m². AL || V ΑΣΦ t
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![A nylon string on a tennis racket is under a tension of 215
N.
Part A
If its diameter is 1.05 mm, by how much is it
lengthened from its untensioned length of 30.0 cm ?
Use ENylon = 5.00 × 10⁹ N/m².
ΔΙ
=
浴
ΑΣΦ
?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffe12d47a-f1d5-457f-830c-a20bf48d1969%2Fce8fd785-996f-442b-ad48-2e98d473f7d8%2F892t2p_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A nylon string on a tennis racket is under a tension of 215
N.
Part A
If its diameter is 1.05 mm, by how much is it
lengthened from its untensioned length of 30.0 cm ?
Use ENylon = 5.00 × 10⁹ N/m².
ΔΙ
=
浴
ΑΣΦ
?
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