A nutritionist claims that the mean tuna consumption by a person is 3.8 pounds per year. A sample of 70 people shows that the mean tuna consumption by a person is 3.5 pounds per year. Assume the population standard deviation is 1.17 pounds. At a = 0.07, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. OA. Ho: HS3.8 H: u> 3.8 O B. Ho: H#3.5 OC. Ho: H=3.8 H: =3.5 H:H#3.8 O D. Ho: H>3.8 HHS3.8 O E. Ho: us3.5 OF. Ho: H> 3.5 H:us3.5 H:u>3.5 (b) Identify the standardized test statistic, z. z= (Round to two decimal places as needed.) (c) Find the P-value. Hint: Keep in mind that P-value depends on the type of test. Left-tailed test: P-value=Area (where Area = the number from the table) Right-tailed test: P-value=1-Area Two-tailed test: P-value=2'Area P-value = (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. Compare P with a and then State your conclusion. O B. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8 pounds. O A. Reject Hn. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8 pounds. O C. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8 pounds. O D. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8 pounds.
A nutritionist claims that the mean tuna consumption by a person is 3.8 pounds per year. A sample of 70 people shows that the mean tuna consumption by a person is 3.5 pounds per year. Assume the population standard deviation is 1.17 pounds. At a = 0.07, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. OA. Ho: HS3.8 H: u> 3.8 O B. Ho: H#3.5 OC. Ho: H=3.8 H: =3.5 H:H#3.8 O D. Ho: H>3.8 HHS3.8 O E. Ho: us3.5 OF. Ho: H> 3.5 H:us3.5 H:u>3.5 (b) Identify the standardized test statistic, z. z= (Round to two decimal places as needed.) (c) Find the P-value. Hint: Keep in mind that P-value depends on the type of test. Left-tailed test: P-value=Area (where Area = the number from the table) Right-tailed test: P-value=1-Area Two-tailed test: P-value=2'Area P-value = (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. Compare P with a and then State your conclusion. O B. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8 pounds. O A. Reject Hn. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8 pounds. O C. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8 pounds. O D. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8 pounds.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A nutritionist claims that the mean tuna consumption by a person is 3.8 pounds per year. A sample of 70 people shows that the mean tuna consumption by a person is 3.5 pounds per year. Assume the population standard deviation is 1.17
pounds. At a = 0.07, can you reject the claim?
(a) Identify the null hypothesis and alternative hypothesis.
O A. Ho: HS3.8
H: > 3.8
O B. Ho: H#3.5
Ha: H= 3.5
OC. Ho: H= 3.8
Ha:H43.8
O D. Ho: H>3.8
ΟΕ. H :μs 3.5
H:u>3.5
OF. Ho: H>3.5
H:Hs3.8
H: us3.5
(b) Identify the standardized test statistic, z.
z= (Round to two decimal places as needed.)
(c) Find the P-value.
Hint: Keep in mind that P-value depends on the type of test.
Left-tailed test: P-value=Area
Right-tailed test: P-value=1-Area
Two-tailed test: P-value=2'Area
(where Area = the number from the table)
P-value = (Round to three decimal places as needed.)
(d) Decide whether to reject or fail to reject the null hypothesis
Compare P with a and then State your conclusion.
O B. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8
pounds.
O A. Reject Hn. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8 pounds.
O C. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8 pounds. O D. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.8
pounds.
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