A nursing school professor is interested in determining how her college students compare to the national average when it comes to the Final Practicum Exam. The exam has a µ = 100 and σ = 20. There has been no evidence to suggest whether those seniors score better or worse than the national average and she is curious as to how her class (N=17) compares. Data Students Exam Score112021003110490513061237101811591111099111051211913128141091598169517102Write the null and alternative hypothesis in statistical form: Determine the mean for the sample: Apply the z-test formula What is your alpha level set to? α Determine the critical value(s) (Zcrit) Label the critical value(s) and indicate the position of the Zobt on the distribution Write the z result in the correct form:

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Description: A nursing school professor is interested in determining how her college students compare to the national average when it comes to the Final Practicum Exam. The exam has a µ = 100 and σ = 20. There has been no evidence to suggest whether those seniors

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A nursing school professor is interested in determining how her college students compare to the national average when it comes to the Final Practicum Exam. The exam has a µ = 100 and σ = 20. There has been no evidence to suggest whether those seniors score better or worse than the national average and she is curious as to how her class (N=17) compares.

Data

Students Exam Score

1	120
2	100
3	110
4	90
5	130
6	123
7	101
8	115
9	111
10	99
11	105
12	119
13	128
14	109
15	98
16	95
17	102

Write the null and alternative hypothesis in statistical form:

Determine the mean for the sample:

Apply the z-test formula

What is your alpha level set to? α

Determine the critical value(s) (Zcrit)

Label the critical value(s) and indicate the position of the Zobt on the distribution

Write the z result in the correct form:

Expert Solution

Step 1

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As the Null Hypothesis is set up for possible rejection, hence

$Null Hypothesis (H_{0}) : μ_{Seniors} = μ_{National average}, i . e there is no difference between the scores of the seniors and the national average Alternative Hypothesis (H_{1}) : μ_{Seniors} \neq μ_{National average} where, μ_{Seniors} is the mean score of seniors from the population, and μ_{Natinal average} is the national average (mean) score .$

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