A numerical example may help to illustrate the geometry involved in Stokes’ theorem. Consider the portion of a sphere shown in Figure 7.17. The surface is specified by r = 4, 0 < 0 < 0.17,0 < ¢ < 0.37, and the closed path forming its perimeter is com- posed of three circular arcs. We are given the field H = 6r sin øa, +18r sin 0 cos pa, and are asked to evaluate each side of Stokes' theorem.
A numerical example may help to illustrate the geometry involved in Stokes’ theorem. Consider the portion of a sphere shown in Figure 7.17. The surface is specified by r = 4, 0 < 0 < 0.17,0 < ¢ < 0.37, and the closed path forming its perimeter is com- posed of three circular arcs. We are given the field H = 6r sin øa, +18r sin 0 cos pa, and are asked to evaluate each side of Stokes' theorem.
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![A numerical example may help to illustrate the geometry involved in Stokes' theorem.
Consider the portion of a sphere shown in Figure 7.17. The surface is specified by r =
4, 0 < 0 < 0.17 , 0 < ¢ < 0.37, and the closed path forming its perimeter is com-
posed of three circular arcs. We are given the field H = 6r sin øa, + 18r sin 0 cos pas
and are asked to evaluate each side of Stokes' theorem.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1f2495b5-73c5-4f98-92c7-665f598a84f8%2Fcd13f55a-0812-43c2-a7ad-12adf71ca40d%2Fz0tjp4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A numerical example may help to illustrate the geometry involved in Stokes' theorem.
Consider the portion of a sphere shown in Figure 7.17. The surface is specified by r =
4, 0 < 0 < 0.17 , 0 < ¢ < 0.37, and the closed path forming its perimeter is com-
posed of three circular arcs. We are given the field H = 6r sin øa, + 18r sin 0 cos pas
and are asked to evaluate each side of Stokes' theorem.
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