A nucleus traveling at speed vnucleus = c(1 - 10-5) decays with the emission of a particle of speed vdecay particle = c(1 - 2 x 10-4) at an angle of 45°, as shown in the diagram above. i) What is the velocity (speed and direction) of the decay particle on transforming to the stationary frame of reference of the nucleus. Clearly explain the quantities used in your evaluation, and show the directions and signs of quantities. Give the speed of the decay particle in the form c(1 - ?). ii) If the decay particle was an electron, what was its total energy in the rest frame of the nucleus? What was its total energy in the original frame shown in the above diagram? Give your answers in units of MeV.

icon
Related questions
Question

A nucleus traveling at speed vnucleus = c(1 - 10-5) decays with the emission of a particle of speed vdecay particle = c(1 - 2 x 10-4) at an angle of 45°, as shown in the diagram above.

i) What is the velocity (speed and direction) of the decay particle on transforming to the stationary frame of reference of the nucleus. Clearly explain the quantities used in your evaluation, and show the directions and signs of quantities. Give the speed of the decay particle in the form c(1 - ?).

ii) If the decay particle was an electron, what was its total energy in the rest frame of the nucleus? What was its total energy in the original frame shown in the above diagram?
Give your answers in units of MeV.

Vdecay particle
450
Vnucleus
Transcribed Image Text:Vdecay particle 450 Vnucleus
Expert Solution
steps

Step by step

Solved in 2 steps

Blurred answer