(a) Н—С—С—С—С—СEN (b) Н—О—с--с—о—н (с) Н—N—N—H

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Predict the molecular geometry of each of the following
molecules:

(a) Н—С—С—С—С—СEN
(b) Н—О—с--с—о—н
(с) Н—N—N—H
Transcribed Image Text:(a) Н—С—С—С—С—СEN (b) Н—О—с--с—о—н (с) Н—N—N—H
Expert Solution
Step 1

(a)Given molecule is

Chemistry homework question answer, step 1, image 1

The shape of the molecule is determined by the geometry possess by the carbon atom present in the molecule.

From the given structure, it is clear that each carbon (C) atom has two electron domains which are bonding. Therefore, the geometry of electron domain is linear having sp hybridization. Hence, the molecule has linear shape.

Step 2

(b)Given molecule is

Chemistry homework question answer, step 2, image 1

The shape of the molecule is determined by the geometry possess by the carbon atom present in the molecule.

From the given structure, it is clear that each carbon (C) atom at the center of the molecule has three electron domains which are bonding. Therefore, the geometry of electron domain is trigonal planar having sp2 hybridization. The carbon and oxygen atoms are arranged in the plane and H atoms are free to rotate in and out of the plane. Hence, the molecule has trigonal planar shape.

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