(a) nsider the change of variable from cartesian coordinates (x, y, z) to coordi- nates (r, y, 0) in R². X = exp(r) cos y cos 0, y = exp(r) sin 0, We will assume that y = [0, 2π) and 0 € [-π/2, π/2]. (i) Show that exp(r) = x² + y² + z²2. (ii) Compute the Jacobian of this transformation. I.e. find the determinant of the matrix z = exp(r) sin cos 0. ах ах ах др до до ду ду ду ar ap 20 əz əz əz or οφ οθ (iii) For € (0, π) and 0 € (-π/2, π/2), express r, y and in terms of x, y and z.

Calculus: Early Transcendentals
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Chapter1: Functions And Models
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Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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(a) Consider the change of variable from cartesian coordinates (x, y, z) to coordi-
nates (r, y, 0) in R².
x = exp(r) cos y cos 0,
y = exp(r) sin 0,
We will assume that y = [0, 2π) and 0 € [-π/2, π/2].
(i) Show that exp(r) = √x² + y² + z².
(ii) Compute the Jacobian of this transformation. I.e. find the determinant of
the matrix
'дх
др
ах ах
до
до
ду
z = exp(r) sin cos 0.
до до
əz əz əz
др
др до до
(iii) For y € (0, π) and 0 € (−π/2, π/2), express r, 4 and 0 in terms of x, y
and z.
(b) Consider a box with square base and no lid which has width x > 0 and height
h> 0. It has area a(x, h) = x² + 4hx and volume v(x, h) = hx².
(i) What is the maximum volume of such a box when it has fixed area A?
(ii) Is it also possible to minimise the volume of the box, keeping the area fixed?
Explain your answer.
Transcribed Image Text:(a) Consider the change of variable from cartesian coordinates (x, y, z) to coordi- nates (r, y, 0) in R². x = exp(r) cos y cos 0, y = exp(r) sin 0, We will assume that y = [0, 2π) and 0 € [-π/2, π/2]. (i) Show that exp(r) = √x² + y² + z². (ii) Compute the Jacobian of this transformation. I.e. find the determinant of the matrix 'дх др ах ах до до ду z = exp(r) sin cos 0. до до əz əz əz др др до до (iii) For y € (0, π) and 0 € (−π/2, π/2), express r, 4 and 0 in terms of x, y and z. (b) Consider a box with square base and no lid which has width x > 0 and height h> 0. It has area a(x, h) = x² + 4hx and volume v(x, h) = hx². (i) What is the maximum volume of such a box when it has fixed area A? (ii) Is it also possible to minimise the volume of the box, keeping the area fixed? Explain your answer.
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