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A normally consolidated clay is consolidated under a stress of 03 =125 kPa, then sheared undrained in a triaxial compression. The principal stress difference (deviatoric stress) at failure is(o1 – 03)f =250 kPa and the induced pore - pressure isAuf =40 kPa. Calculate the minor principal stress at failure in term of %3D effective stress 03f? (Unit: kPa)

A normally consolidated clay is consolidated under a stress of 03 =125 kPa, then sheared undrained in a triaxial compression. The principal stress difference (deviatoric stress) at failure is(o1 – 03)f =250 kPa and the induced pore - pressure isAuf =40 kPa. Calculate the minor principal stress at failure in term of %3D effective stress 03f? (Unit: kPa)

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question 10 A normally consolidated clay is consolidated under a stress of 03 =125 kPa, then sheared undrained in a triaxial compression. The principal stress difference (deviatoric stress) at failure is(o1 pressure isAuf effective stress 0? (Unit: kPa) %3D 03)f =250 kPa and the induced pore - =40 kPa. Calculate the minor principal stress at failure in term of Your Answer: CS Scanned with CamScanner
Transcribed Image Text:Question 10 A normally consolidated clay is consolidated under a stress of 03 =125 kPa, then sheared undrained in a triaxial compression. The principal stress difference (deviatoric stress) at failure is(o1 pressure isAuf effective stress 0? (Unit: kPa) %3D 03)f =250 kPa and the induced pore - =40 kPa. Calculate the minor principal stress at failure in term of Your Answer: CS Scanned with CamScanner
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