A normal distributed population has parameters μ = 145.7 and o= 5.5. If a random sample of size n = 79 is selected, a. What is the mean of the distribution of sample means? f= b. What is the standard deviation of the distribution of sample means? Round to two decimal places. σ =

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Chapter1: Combinatorial Analysis
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A normal distributed population has parameters \( \mu = 145.7 \) and \( \sigma = 5.5 \). If a random sample of size \( n = 79 \) is selected,

a. What is the mean of the distribution of sample means?

\[ \mu_{\bar{x}} = \]
  
b. What is the standard deviation of the distribution of sample means? *Round to two decimal places.*

\[ \sigma_{\bar{x}} = \]
Transcribed Image Text:A normal distributed population has parameters \( \mu = 145.7 \) and \( \sigma = 5.5 \). If a random sample of size \( n = 79 \) is selected, a. What is the mean of the distribution of sample means? \[ \mu_{\bar{x}} = \] b. What is the standard deviation of the distribution of sample means? *Round to two decimal places.* \[ \sigma_{\bar{x}} = \]
A population of values has a normal distribution with \( \mu = 51.9 \) and \( \sigma = 65.5 \). If a random sample of size \( n = 10 \) is selected,

a. Find the probability that a single randomly selected value is less than 109.9. *Round your answer to four decimals.*  
\[ P(X < 109.9) = \, \boxed{} \]

b. Find the probability that a sample of size \( n = 10 \) is randomly selected with a mean less than 109.9. *Round your answer to four decimals.*  
\[ P(M < 109.9) = \, \boxed{} \]
Transcribed Image Text:A population of values has a normal distribution with \( \mu = 51.9 \) and \( \sigma = 65.5 \). If a random sample of size \( n = 10 \) is selected, a. Find the probability that a single randomly selected value is less than 109.9. *Round your answer to four decimals.* \[ P(X < 109.9) = \, \boxed{} \] b. Find the probability that a sample of size \( n = 10 \) is randomly selected with a mean less than 109.9. *Round your answer to four decimals.* \[ P(M < 109.9) = \, \boxed{} \]
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