A normal distributed population has parameters μ = 145.7 and o= 5.5. If a random sample of size n = 79 is selected, a. What is the mean of the distribution of sample means? f= b. What is the standard deviation of the distribution of sample means? Round to two decimal places. σ =
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- A population of N = 5 scores has a mean of u = 20 and a standard deviation of o = 4. Which of the following is the correct Interpretation of the standard deviation? O The average distance of scores from the mean of p- 20 is 5 points. O The average distance of scores from the mean of u = 20 is 1 point. The average distance of scores from the mean of u = 20 is 4 points. O The average squared distance of scores from the mean of u = 20 is 4 points.Please helpIn the entire population of a certain type of tree, the mean height of the trees is μ = 168.8 ft and the standard deviation is σ = 43.6 ft. You collect a random sample of n=22 trees. The distribution of these sample means is shown below. Each tick mark on the horizontal axis is a distance of one more standard error. Complete the indicated boxes, correct to two decimal places. mean of distribution=168.8 standard error=9.30 Note: The left box is 2 standard errors below the mean. The middle box is the mean. The right box is 2 standard errors above the mean.
- This assignment is worth 1 points. The extra point will be added to your overall course grade. For example: if you receive an 88% in the course you can receive up to 1 point giving you a new score of 89%. The following rubric will be used. 0.25 point for drawing the normal distribution curve with the mean value labeled on the curve and the appropriate area shaded. 0.25 point for determining the value of the standard deviation of the sample mean. 0.5 point for finding the correct probability. All work must be shown in order to receive any credit. Please upload your completed assignment here. The length of time taken on the SAT for a group of students is normally distributed with a mean of 2.5 hours and a standard deviation of 0.25 hours. A sample size of n = 60 is drawn randomly from the population. Find the probability that the sample mean is between two hours and three hours.Use the sample data set to evaluate each of the steps in determining the sample standard deviation 23 20 14 35 28 Give an exact answer, not an approximation, for each step except the standard deviation. round the standard deviation to the nearest hundredth.. = = variance, s2 = standard deviation, s =A population has a mean µ = 87 and a standard deviation à = 23. Find the mean and standard deviation of a sampling distribution of sample means with sample size n = 257. ox = (Simplify your answer.) (Type an integer or decimal rounded to three decimal places as needed.) 33
- A population has a mean µ = 70 and a standard deviation o = 28. Find the mean and standard deviation of a sampling distribution of sample means with sample size n = 261. P = (Simplify your answer.) = (Type an integer or decimal rounded to three decimal places as needed.)In a population of a certain species of newt, the mean length of the newts is μ= 63 inches and the standard deviation is σ= 3.4 inches. You collect a random sample of n=16 newts. The bell curve below represents the distribution of these sample means. The scale on the horizontal axis is the standard error of the sampling distribution. Complete the indicated boxes, correct to two decimal places. mean of distribution= standard error= Note: The left box is 2 standard errors below the mean. The middle box is the mean. The right box is 2 standard errors above the mean.A researcher collects data that represents the average number of hours of sleep in the last two nights by 8 depressed patients and 9 non-depressed patients. The researcher is interested in whether the two groups reliably differ in the amount of sleep they get. Use Jamovi to calculate t-obt and the p value.
- A normal distribution has mean 62.1 and standard deviation 2.42. Find the data value corresponding to the following value of z. z= -1.33A distribution of values is normal with a mean of 41.2 and a standard deviation of 24.2. Find P38, which is the score separating the bottom 38% from the top 62%. P38 = Enter your answer as a number accurate to 1 decimal place. Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Submit Question abc esc F1 F2 F3 F4 F5 F6 %23 3. Q W R 454P3. Show that the mle of unknown standard deviation when the mean is known is different from the sample standard deviation when the random sample is taken from a normal population characterized by two parameters, mean and variance. Which estimator is unbiased? Justify your answer. Show that a sample mean is a minimum variance unbiased estimator of the mean of a normal population with known variance.