A nonhomogeneous equation and a particular solution are given. Find a general solution for the equation. y” - y=12t, yp(t) = - 12t The general solution is y(t) = (Do not use d, D, e, E, i, or I as arbitrary constants since these letters already have defined meanings.)

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.3: The Natural Exponential Function
Problem 12E
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**Finding the General Solution of a Nonhomogeneous Equation**

### Problem Statement
Given a nonhomogeneous equation and a particular solution, the goal is to find the general solution for the equation:

\[ y'' - y = 12t, \quad y_p(t) = -12t \]

### Solution Guidelines
The general solution for \( y(t) \) comprises two parts: the general solution of the corresponding homogeneous equation and the particular solution to the nonhomogeneous equation.

#### 1. Solve the Homogeneous Equation
First, solve the corresponding homogeneous equation:

\[ y'' - y = 0 \]

The characteristic equation for this differential equation is:

\[ r^2 - 1 = 0 \]

This factors as:

\[ (r - 1)(r + 1) = 0 \]

Thus, the roots are \( r = 1 \) and \( r = -1 \).

Therefore, the general solution to the homogeneous equation is:

\[ y_h(t) = C_1 e^t + C_2 e^{-t} \]

#### 2. Incorporate the Particular Solution
Given the particular solution to the nonhomogeneous equation:

\[ y_p(t) = -12t \]

#### 3. Form the General Solution
Combine the solutions obtained:

\[ y(t) = y_h(t) + y_p(t) \]

\[ y(t) = C_1 e^t + C_2 e^{-t} - 12t \]

In conclusion, the general solution to the given nonhomogeneous differential equation is:

\[ y(t) = C_1 e^t + C_2 e^{-t} - 12t \]

(Note: It is specified not to use \( d \), \( D \), \( e \), \( E \), \( i \), or \( I \) as arbitrary constants since these letters already have defined meanings.)

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Transcribed Image Text:--- **Finding the General Solution of a Nonhomogeneous Equation** ### Problem Statement Given a nonhomogeneous equation and a particular solution, the goal is to find the general solution for the equation: \[ y'' - y = 12t, \quad y_p(t) = -12t \] ### Solution Guidelines The general solution for \( y(t) \) comprises two parts: the general solution of the corresponding homogeneous equation and the particular solution to the nonhomogeneous equation. #### 1. Solve the Homogeneous Equation First, solve the corresponding homogeneous equation: \[ y'' - y = 0 \] The characteristic equation for this differential equation is: \[ r^2 - 1 = 0 \] This factors as: \[ (r - 1)(r + 1) = 0 \] Thus, the roots are \( r = 1 \) and \( r = -1 \). Therefore, the general solution to the homogeneous equation is: \[ y_h(t) = C_1 e^t + C_2 e^{-t} \] #### 2. Incorporate the Particular Solution Given the particular solution to the nonhomogeneous equation: \[ y_p(t) = -12t \] #### 3. Form the General Solution Combine the solutions obtained: \[ y(t) = y_h(t) + y_p(t) \] \[ y(t) = C_1 e^t + C_2 e^{-t} - 12t \] In conclusion, the general solution to the given nonhomogeneous differential equation is: \[ y(t) = C_1 e^t + C_2 e^{-t} - 12t \] (Note: It is specified not to use \( d \), \( D \), \( e \), \( E \), \( i \), or \( I \) as arbitrary constants since these letters already have defined meanings.) ---
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