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- Suppose the number of cell phones in a household has a binomial distribution with parameters n = 15 and p = 85%. Find the probability of a household having: (a) 5 or 12 cell phonesA company has seven applicants for two positions: three women and four men. Suppose that the seven applicants are equally qualified and that no preference is given for choosing either gender. Let x equal the number of women chosen to fill the two positions. (a) Write the formula for p(x), the probability distribution of x. (b) What are the mean ? and variance ?2 of this distribution? (Round your mean to one decimal place and your variance to two decimal places.)Assume that the normal distribution can be used to approximate the following binomial distribution question. A survey of adults found that 6% say their favorite sport is auto racing. You randomly select 400 adults and ask them to name their favorite sport. Complete parts (a) and (b). (a) Find the probability that the number of people who say auto racing is their favorite sport is at most 30. (b) Find the probability that the number of people who say auto racing is their favorite sport is more than 33. (Round to four decimal places as needed.)
- In the probability distribution to the right, the random variable X represents the number of marriages an individual aged 15 years or older has been involved in. Complete parts (a) through (f) below. Describe the shape of the distribution. The distribution is multimodal and is skewed right. (c) Compute and interpret the mean of the random variable X. Hx = 0.924 marriages (Type an integer or a decimal. Do not round.) Which of the following interpretations of the mean is correct? A. If many individuals aged 15 year or older were surveyed, one would expect the mean number of marriages to be the mean of the random variable. B. The observed number of marriages will be less than the mean number of marriages for most individuals. C. The observed number of marriages will be equal to the mean number of marriages for most individuals. D. If any number of individuals aged 15 year or older were surveyed, one would expect the mean number of marriages to be the mean of the random variable. (d)…In a recent poll, the Gallup Organization found that 45% of adult Americans believe that the overall state of moral values in the United Next qdestion survey of a random sample of 15 adults in this country is conducted in which they are asked to disclose their feelings on the overall state of moral values, complete parts (a) through (g) below. (c) Using the binomial distribution, find and interpret the probability that exactly 10 of those surveyed feel the state of morals is poor. The probability that exactly 10 of those surveyed feel the state of morals is poor is. (Round to four decimal places as needed.) Interpret the results. In 100 trials of this experiment, we expect about to result in exactly 10 adults who feel the state of morals is poor. (Round to the nearest whole number as needed.) (d) Using the binomial distribution, find and interpret the probability that no more than 4 of those surveyed feel the state of morals is poor. The probability that no more than 4 of those…Which of the following is a legitimate probability distribution? (d) No. Prob 0.10 (e) No. Prob. (a) No. Prob. 1/4 (b) No. Prob. (c) No. Prob. 0.1 1. 1/4 2. 2. 0.2 2. 0.11 2. 3. 3. 3. 3. 0.25 3. -1 3 1/4 1/4 0.05 0.26 4. 4 4. 4. 0.3 4 4 1/4 04 O a Oc
- (first part of question is attached) (e) What is the probability that the sample proportion of students of adults living with parents or other relatives is higher than 0.3? (f) What is the probability that the sample proportion of adults living alone is between 0.1 and 0.15?On average, you receive 2.6 pieces of junk mail a day. Assume that the number of pieces of junk mail you receive each day follows the Poisson distribution What is the probability of receiving more than three pieces of junk mail today? O a. 0.2939 O b. 0.2639 O c. 0.2693 d. 0.236932% of working mothers do not have enough money to cover their health insurance deductibles. You randomly select six working mothers and ask them whether they have enough money to cover their health insurance deductibles. The random variable represents the number of working mothers who do not have enough money to cover their health insurance deductibles. Complete parts (a) (a) Construct a binomial distribution using n=6 and p=0.32. x P(x) 0 1 2 3 4 5 6 (Round to the nearest thousandth as needed.)
- A. What is the difference between Binomial Distribution and Negative Binomial Distribution? Explain with examples.You are looking for the probability to draw 3 aces in 5 attempts from a deck of cards. There are 52 cards in the deck and 4 of them are aces. Explain why the poisson is not a good choice for describing this data-generating process. Which distribution would you use instead? No calculations necessary.
