A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or theflu. In the survey, 63% said that they are most likely to sleep and 19% said that they would watch television. Although the sample size was not reported, typicallyopinion polls include approximately 1,000 randomly selected respondents.ata. Assuming a sample size of 1,000 for this poll, construct a 90% confidence interval for the true percentage of all adults who would choose to sleep when they are athomesick.ntThe 90% confidence interval is ( LD.tu(Round to the nearest hundredth as needed.)b. If the true percentage of adults who would choose to sleep when they are at home sick is 70%, would you be surprised?ShO NoGraO Yesnch

It is given that the sample size for this poll is 1000. n=1000 63% of the adults says in the survey…

A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or the flu. In the survey, 63% said that they are most likely to sleep and 19% said that they would watch television. Although the sample size was not reported, typically opinion polls include approximately 1,000 randomly selected respondents. a. Assuming a sample size of 1,000 for this poll, construct a 90% confidence interval for the true percentage of all adults who would choose to sleep when they are at home sick. The 90% confidence interval is (.). (Round to the nearest hundredth as needed.) b. If the true percentage of adults who would choose to sleep when they are at home sick is 70%, would you be surprised? No Yes

A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or the flu. In the survey, 63% said that they are most likely to sleep and 19% said that they would watch television. Although the sample size was not reported, typically opinion polls include approximately 1,000 randomly selected respondents. a. Assuming a sample size of 1,000 for this poll, construct a 90% confidence interval for the true percentage of all adults who would choose to sleep when they are at home sick. The 90% confidence interval is (.). (Round to the nearest hundredth as needed.) b. If the true percentage of adults who would choose to sleep when they are at home sick is 70%, would you be surprised? No Yes

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The city council of Pine Bluffs is considering increasing the number of police in an effort to reduce crime. Before making a final decision, the council asked the chief of police to survey other cities of similar size to determine the relationship between the number of police and the number of crimes reported. The chief gathered the following sample information. City Oxford Starksville Danville Athens ……….... Police 23 24 30 33 Number of Crimes 18 15 Click here for the Excel Data File 9 11 Number of crimes City Holgate Carey Whistler Woodville > Answer is complete but not entirely correct. 40.6081 X (90.0408) ► x Answer is complete and correct. 19✔ Police 24 20 19 27 a. Determine the regression equation. (Negative amounts should be indicated by a minus sign. Round your answers to 4 decimal places.) Number of Crimes 9 22 24 10 b. Estimate the number of crimes for a city with 21 police officers. (Round your answer to the nearest whole number.)
A researcher divided subjects into two groups according to gender and then selected a fixed proportion of members from each group for his sample. What sampling method was the researcher using? A. Stratified sample. B. Simple random sample. C. Voluntary response sample. D. Cluster sample.
Researchers want to estimate the percentage of people who thought drinking and driving was a serious problem. Reserchers waited outside a bar to question people. They usually find 11%of bar patrons believe drinking and driving is a serious problem. a. identify the populatin of interest b. identify the sample c. identify the population parameter of interest d. identifywho if anyone was left out of the study
sixty-five percent of those surveyed reply No to a certain question. If 234 reply No, what is the sample size?
A vaccine to prevent a severe virus was given to children within the first year of life as part of a drug study. The study reported that of the 3456bchildren randomly assigned the vaccine, 58 got the virus. Of the 1606 children randomly assigned the placebo, 46 got the virus. a. Find the sample percentage of children who caught the virus in each group. Is the sample percentage lower for the vaccine group, as investigators hoped? b. Determine whether the vaccine is effective in reducing the chance of catching the virus, using a significance level of 0.01.The first few steps of the hypothesis-testing procedure are given. Complete the procedure.
QuickVote. TalkBack Live, a production of CNN, conducted on-line surveys on various issues. One survey, called a QuickVote, of 680 people asked “Would you vote for a third-party candidate?” Of the 680 people surveyed, 608 (89.4%) responded “yes” and 72 (10.6%) responded “no.” Beneath the vote tally, the following statement regarding the sampling procedure was found: This QuickVote is not scientific and reflects the opinions of only those Internet users who have chosen to participate. The results cannot be assumed to represent the opinions of Internet users in general, nor the public as a whole. The QuickVote sponsor is not responsible for content, functionality or the opinions expressed therein. Discuss the preceding statement in light of what you have learned
Consider a sample with data values of 27, 25, 20, 15, 30, 34, 28, and 25. Compute the 19th, 24th, 65th, and 75th percentiles. If needed, round your answers to two decimal digits. Percentile Value 19% 24% 65% 75%
Sample surveys on sensitive issues can give different results depending on how the question is asked. A University of Wisconsin study randomly divided 2400 respondents into three groups. All participants were asked if they had ever used cocaine. One group of 800 was interviewed by phone; 21% said they had used cocaine. Another 800 people were asked the question in a one-on-one personal interview; 25% said “Yes.” The remaining 800 were allowed to make an anonymous written response; 28% said “Yes.”101. Was this an experiment or an observational study? Justify your answer.2. Make a two-way table of responses about cocaine use by how the survey was administered.3. Are the differences between the three groups statistically significant? Give appropriate evidence to support your answer
You are the operations manager for an airline and you are considering a higher fare level for passengers in aisle seats. How many randomly selected air passengers must you survey? Assume that you want to be 95% confident that the sample percentage is within 3.5 percentage points of the true population percentage. a. Assume that nothing is known about the percentage of passengers who prefer aisle seats. b. Assume that a prior survey suggests that about 33% of air passengers prefer an aisle seat.
In an AOL survey of Internet users, this question was posted online: "Have you ever been hit by a computer virus?" Among the 170,063 responses, 63% answered "yes." What term is used to describe this type of survey in which the people surveyed consist of those who chose to respond? What is wrong with this type of sampling method?
In politics, marketing, etc. we often want to estimate a percentage or proportion p. One calculation in statistical polling is the margin of error - the largest (reasonble) error that the poll could have. For example, a poll result of 72% with a margin of error of 4% indicates that p is most likely to be between 68% and 76% (72% minus 4% to 72% plus 4%). In a (made-up) poll, the proportion of people who like dark chocolate more than milk chocolate was 39% with a margin of error of 1.3%. Describe the conclusion about p using an absolute value inequality. The answer field below uses the symbolic entry option in Mobius. That lets you type in a vertical bar | to represent absolute values. Also, when you type in < and then =, the symbolic entry option will automatically convert that to ≤ . In the same way, if you type in > and then =, the symbolic entry option will automatically convert that to ≥. Be sure to use decimal numbers in your answer (such as using 0.40 for 40%).
In 1942, an organization surveyed 1100 adults and asked, "Are you a total abstainer from, or do you on occasion consume, alcoholic beverages?" Of the 1100 adults surveyed, 440 indicated that they were total abstainers. In a recent survey, the same question was asked of 1100 adults and 418 indicated that they were total abstainers. Complete parts (a) and (b) below. (a) Determine the sample proportion for each sample. and respectively. The proportions of the adults who took the 1942 survey and the recent survey who were total abstainers are (Round to three decimal places as needed.)