A newspaper reported on the results of an opinion poll in which adults were asked what one thing they are most likely to do when they are home sick with a cold or flu. In the survey 63 % said they are most likely to sleep. Assuming a sample sixe of 1,000, construct a 90% confidence interval for the true percentage of all asults who would choose to sleep when they are sick

Q: Out of 300 people sampled, 156 had kids. Based on this construct a 90% confidence interval for the…

A: X = 156 N = 300

Q: ) When 415 junior college students were surveyed, 150 said they have a passport. Construct a 95%…

A:

Q: A June 2009 Harris Interactive poll asked people their opinions about the influence of advertising…

A: The value of z at 98% confidnce level is 2.326, which can be obtained by using the standard normal…

Q: In a sample of 100, 40 said they preferred Pepsi to coke. A 95% confidence interval for the…

A:

Q: What proportion of the sample reported that they had been cyberbullied?

A: Givensample size(n)=14795No.of respondents say yes they had been cyberbullied(x1) = 2219No.of…

Q: In a random sample of 500 adults, 410 described themselves as vegetarians. Construct a 95%…

A: We have been provided with the following information about the adults who describe themselves as…

Q: qualities as options, one of which is "communicator", as the most important quality for an effective…

A: It is given that  Favourable cases, X = 121 Sample size, n = 275 Sample proportion, p^ = X/n…

Q: In a survey of 4061 ​adults, 738 say they have seen a ghost. Construct a​ 99% confidence interval…

A: In this question, it has been given that 738 people out of 4061 people have seen the ghost, we have…

Q: a newspaper article stated that the us supreme court received 812 letters from around the country on…

A: To find the 95% confidence interval for the true proportion of all American adults who feel that…

Q: The following table shows the results of a survey in which 1017 adults from the United States, 1060…

A: (1)

Q: An interactive poll found that 397 of 2,391 adults aged 18 or older have at least one tattoo. A.…

A: Given data: Sample size (n) = 2391 x = 397 adults To construct: 1.95 % confidence interval 2.98%…

Q: In a sports poll, 142 of 500 randomly selected Americans indicated that they consider themselves to…

A: Given that, In a sports poll, 142 of 500 randomly selected Americans indicated that they consider…

Q: In a sample of 1901 patients who underwent a certain type of surgery, 22% experienced complications.…

A:

Q: The Nielsen company surveyed 257 owners of android phones and found that 217 of them planned to get…

A: From the provided information,

Q: In a survey of 2480 golfers, 372 said they were left-handed. Construct a 92% confidence interval for…

A: GIVEN DATA : Total number of golfers are 2480, Number of left handed golfer are 372        TO FIND :…

Q: Out of 54 randomly selected patients of a local hospital who were surveyed, 49 reported that they…

A: Giventotal patients randomly selected =n = 54total patients who were satisfied = 49proportion of…

Q: Suppose you want to construct a 95% confidence interval for the difference

A:

Q: At one large college, 660 out of the 1500 students surveyed said they plan to take another science…

A: Given that,   x=660,n=1500 The sample proportion is, Critical values: By using the standard normal…

Q: A survey of 41 students in grades 4 through 12 found 63% have classroom Wi-Fi access. Find the 99%…

A: It is given that sample size (n) is 41 and the sample proportion value is 0.63.

2-Proportion Test

In a 2-proportion test, two separate proportions are measured at the same time, and their similarity is evaluated. It is also known as a 2-proportion z-test, and a comparison of two different proportions is done in this method.