A newsgroup is interested in constructing a 99%confidence interval for the proportion of all Americanswho are in favor of a new Green initiative. Of the 663randomly selected Americans surveyed, 306 were infavor of the initiative.Note on rounding: For parts (A) and (B), round allnumerical answers to three decimal places, as needed. Forpart (C) a whole number answer is expected for eachnumerical value.A. What is the critical value for this confidenceinterval?B. (Fill in the blanks) With a 99% confidence, theproportion of all Americans who favor the Greeninitiative is betweenandC. (Fill in the blanks) If many groups of 663 randomlyselected Americans were surveyed, then a differentconfidence interval would be produced from eachpercent of thesegroup. Aboutconfidence intervals will contain the true populationproportion of Americans who favor the Greeninitiative and aboutpercent willnot contain the tru population proportion.CrCT ValueChi-SquR ValueSignific(0 to 0.0.3Degrees45CalcuHow dvaluework?• Enter SThe Inp. Put theIn The• Hit TheFind T• Use ThcalculaOther1. Coeff

From the provided information, Sample size (n) = 663 From which 306 were in favor of the initiative.…

Answered: A newsgroup is interested in…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

A magazine provided results from a poll of 500 adults who were asked to identify their favorite pie. Among the 500 respondents, 11% chose chocolate pie, and the margin of error was given as ±3 percentage points. Given specific sample data, which confidence interval is wider: the 99% confidence interval or the 80% confidence interval? Why is it wider? Choose the correct answer below. O A. A 99% confidence interval must be wider than an 80% confidence interval because it contains 99% of the true population parameters, while the 80% confidence interval only contains 80% of the true population parameters. O B. An 80% confidence interval must be wider than a 99% confidence interval because it contains 100% - 80% = 20% of the true population parameters, while the 99% confidence interval only contains 100% - 99% = 1% of the true population parameters. OC. A 99% confidence interval must be wider than an 80% confidence interval in order to be more confident that it captures the true value of…
The FBI wants to determine the effectiveness of their 1010 Most Wanted list. To do so, they need to find out the fraction of people who appear on the list that are actually caught. Step 2 of 2 : Suppose a sample of 283283 suspected criminals is drawn. Of these people, 9393 were captured. Using the data, construct the 85%85% confidence interval for the population proportion of people who are captured after appearing on the 1010 Most Wanted list. Round your answers to three decimal places.
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
The Pizza Shop wanted to determine what of its customers ordered an only cheese pizza. Out of 90 customers surveyed, 20 ordered only cheese Pizza. What is the 90% confidence interval of the true proportion of customers who order only cheese Pizza?
Call me: A sociologist wants to construct a 99% confidence interval for the proportion of children aged 8 - 10 living in New York who own a smartphone.(a) A survey by the National Consumers League estimated the nationwide proportion to be 0.40 . Using this estimate, what sample size is needed so that the confidence interval will have a margin of error of 0.02 ?
A random sample of 318 students from a large college were asked if they are planning to visit family during Thanksgiving break. Based on this random sample, a 99% confidence interval for the proportion of all students at this college who plan to visit family during Thanksgiving break is 0.78 to 0.98. Which of the following is the correct interpretation of the confidence interval? options: We are 95% confident that the interval from 0.78 to 0.98 captures the true proportion of all students at this college who plan to visit family during Thanksgiving break. We are 95% confident that the interval from 0.78 to 0.98 captures the true proportion of all students in this sample who plan to visit family during Thanksgiving break. We are 95% confident that the interval from 0.78 to 0.98 captures the true proportion of all students at this college who said they plan to visit family during Thanksgiving break. None of these is correct.
How to calculate a 90% confidence interval?
Imagine that you obtain a random sample of 125 M&M candies, and you notice that 28% of these candies are blue. If we convert the sample percentage of 0.28 to a sample proportion (by dividing 28 by 100), we get 0.28.
Two brands of tires were compared for the proportion of defective tires. Random samples of tires were collected from each brand, and the number of defective tires from each brand was recorded. The data is in the following table. Number of defective tires (x) 41 32 n Continental Michelin 320 180 a.Construct a 97% confidence interval for the difference between the two proportions. b.For part a, find the desired sample sizes if you want the Continental sample to be 1.5 times Michelin sample with a sampling error equal to 0.03. c. Conduct a test of hypothesis to determine if the defective rates are the same. Use the P-value to interpret the results (a is not given).
You are interested in constructing a 99% confidence interval for the proportion of all caterpillars that eventually become butterflies. Of the 382 randomly selected caterpillars observed, 54 lived to become butterflies. Round answers to 4 decimal places where possible. a. With 99% confidence the proportion of all caterpillars that lived to become a butterfly is between__ and __.
During the recent US Presidential election exit polls were conducted throughout the nation. A California exit poll showed 64% of 700 women questioned voted for President Biden. Nationally 55% of a sample of 1550 women voted for President Biden. We are interested in estimating (with 95% confidence) the difference between the proportion of California women that voted for President Biden and the proportion of women that voted for Biden nationally. Use the shortcut formula to compute a 95% confidence interval for the difference in the two proportions The confidence interval is A. (. 359, 426) B. (046, .133) C.(-046, .133) D. (.225, 426) E. (.001, .326)
in a poll, 73% of California adults (367 out of 506 surveyed) believe that education is one of the main issues facing California. We want to construct a 90% confidence interval for the true proportion of California adults who believe that education is one of the main issues facing California.- I need help with finding a 90% confidence interval for the population proportion (I also have to round the answer to three decimal places)

SEE MORE QUESTIONS

Recommended textbooks for you

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

MATLAB: An Introduction with Applications

Statistics

ISBN:

9781119256830

Author:

Amos Gilat

Publisher:

John Wiley & Sons Inc

Probability and Statistics for Engineering and th…

Statistics

ISBN:

9781305251809

Author:

Jay L. Devore

Publisher:

Cengage Learning

Statistics for The Behavioral Sciences (MindTap C…

Statistics

ISBN:

9781305504912

Author:

Frederick J Gravetter, Larry B. Wallnau

Publisher:

Cengage Learning

Elementary Statistics: Picturing the World (7th E…

Statistics

ISBN:

9780134683416

Author:

Ron Larson, Betsy Farber

Publisher:

PEARSON

The Basic Practice of Statistics

Statistics

ISBN:

9781319042578

Author:

David S. Moore, William I. Notz, Michael A. Fligner

Publisher:

W. H. Freeman

Introduction to the Practice of Statistics

Statistics

ISBN:

9781319013387

Author:

David S. Moore, George P. McCabe, Bruce A. Craig

Publisher:

W. H. Freeman

SEE MORE TEXTBOOKS