A newly proposed project has a first cost of $ 230815 and estimated annual income of $49110 per year for 10 years. Determine the PW value if the MARR is 11.9% per year.
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A newly proposed project has a first cost of $ 230815 and estimated annual income of $49110 per year for 10 years. Determine the PW value if the MARR is 11.9% per year.
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- Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with tribological (i.e., low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 15% per year, which alternative has the lower present worth? Method First Cost M&O Cost, per Year Salvage Value Life DDM $-240,000 $-30,000 $2,000 2 years LS $-480,000 $-15,000 $23,000 4 years The present worth for the DDM method is $ The present worth for the LS method is $ The (Click to select) v method is selected.Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with tribological (i.e., low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 12% per year, which alternative has the lower present worth? Method First Cost M&O Cost, per Year Salvage Value Life DDM $-130,000 $-45,000 $8,000 2 years The present worth for the DDM method is $ The present worth for the LS method is $ The (Click to select) method is selected. LS $-310,000 $-20,000 $21,000 4 yearsStandby power for pumps at water distribution booster stations can be provided by either gasoline-or diesel-powered engines. The costs for the gasoline engines are as follows: Gasoline First cost, $ Annual M&O, $ per year Salvage value, $ Life, years - 150,000 -41,000 23,000 15 The incremental PW cash flow equation associated with (diesel – gasoline) is 0 = -40,000 + 11,000 (P/A, i, 15) + 16,000(P/F, i, 15) Determine the following: (a) First cost of the diesel engines (b) Annual M&O cost of the diesel engines (c) Salvage value of the diesel engines
- For the cash flows shown, determine the incremental cash flow between machines B and A (a) in year 0, (b) in year 3, and (c) in year 6. Machine A B First cost, $ −15,000 −25,000 AOC, $ per year −1,600 −400 Salvage value, $ 3,000 6,000 Life, years 3 6Dexcon Technologies, Inc., is evaluating two alternatives to produce its new plastic filament with tribological (ie.. low friction) properties for creating custom bearings for 3-D printers. The estimates associated with each alternative are shown below. Using a MARR of 10% per year, which alternative has the lower present worth? Method First Cost M&O Cost, per Year Salvage Value Life DDM $-190,000 $-55,000 $4,000 2 years The present worth for the DDM method is $ The present worth for the LS method is $ The LS method is selected. LS $-430,000 $-25,000 $39,000 4 yearsA company that manufactures magnetic flow meters expects to undertake a project that will have the cash flows estimated. First cost, $ −840,000 Equipment replacement cost in year 2, $ −300,000 Annual operating cost, $/year −890,000 Salvage value, $ 250,000 Life, years 4 At an interest rate of 10% per year, what is the equivalent annual cost of the project? Find the AW value using tabulated factors. The equivalent annual cost of the project is $− .
- A company that manufactures magnetic flow meters expects to undertake a project that will have the cash flows estimated. First cost, $ −900,000 Equipment replacement cost in year 2, $ −300,000 Annual operating cost, $/year −950,000 Salvage value, $ 250,000 Life, years 4 At an interest rate of 10% per year, what is the equivalent annual cost of the project? Find the AW value using tabulated factors. The equivalent annual cost of the project is $− . Note:- Do not provide handwritten solution. Maintain accuracy and quality in your answer. Take care of plagiarism. Answer completely. You will get up vote for sure.Evaluate a combined cycle power plant on the basis of the Present Worth Method (PW) when MARR is 12 % per year.Pertinent cost data are as follows: (Power Plant (thousands of $) Investment Cost: $12693 Useful life: 15 ears Market Value (EOY 15) $3,000 Annual Operating expenses: $1,000 Overhaul cost-end of 5th year: $1897 Overhaul cost-end of 10th year. $1819An equipment costs 325,000.00 and has a life of 4 years with a salvage value of 50,000. Determine the capitalized cost of the equipment if the rate of interest is 16% per annum.
- A chemical processing corporation is considering two methods to dispose of a non-hazardous chemical sludge: land application and fluidized-bed incineration. The estimates for each method are shown below. Use the Annual Worth (AW) method at interest 10% per year to select the better alternative Land Application Incineration First cost, $ - 130,000 - 900,000 Annual operating cost, $ - 95,000 - 60,000 Salvage value, $ 25,000 300,000 Life, years 3 10% TABLE 15 Discrete Cash Flow: Compound Interest Factors 10% Single Payments Uniform Serles Payments Arithmetic Gradients Compound Amount Present Sinking Fund Compound Amount Capital Recovery A/P Gradient Present Worth P/G Gradient Uniform Series A/G Present Worth Worth F/P P/F A/F F/A P/A 1.00000 1.0000 2.1000 1.10000 0.57619 0.40211 1.1000 0.9091 0.9091 0.8264 0.7513 2 1.2100 0.47619 1.7355 0.8264 0.4762 2.4869 2.3291 4.3781 6.8618 9.6842 1.3310 0.30211 3.3100 0.9366 1.3812 0.31547 0.26380 0.22961 0.20541 0.21547 4.6410 3.1699 0.6830 0.6209 4…ChemCo Enterprises is the manufacturer of Ultra-Dry, a hydrophobic coating that will waterproofanything. Over a 5 year period, the costs associated with the pilot test product line were as follows: first cost of $43,000 and annual costs of $18,000. Annual revenue was $40,000 and used equipment was salvaged for $4,000. What rate of return did the company make on the product?Advanced Technologies, Inc. is evaluating two alternatives to produce its new plastic filament with tribological (low friction) properties for creating custom bearing for 3-D printers. The estimates associated with its alternatives are shown below. Use LCM way and a MARR of 20% per year. Method DDM LS First Cost $ -165,000 -375,000 M&O cost, $/year -50,000 -25,000 Salvage value $ 30,000 Life, years 2 4 Which Method should be selected? O a. Select Method DDM since it generates higher revenue. b. Select Method LS since it generates higher revenue. c. Select Method DDM since it is less costly. O d. Select Method LS since it is less costly.